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Thepotemich [5.8K]
3 years ago
13

Solve x'=5t(sqrt(x)) x(0)=1

Mathematics
1 answer:
LekaFEV [45]3 years ago
8 0

Answer:

2\sqrt{x}=\frac{5t^2}{2}+2

Step-by-step explanation:

Given: \frac{\mathrm{d} x}{\mathrm{d} t}=5t\sqrt{x}\,,\, x(0)=1

Solution:

A differential equation is said to be separable if it can be written separately as  functions of two variables.

Given equation is separable.

We can write this equation as follows:

\frac{dx}{\sqrt{x}}=5t\,dt

On integrating both sides, we get

\int \frac{dx}{\sqrt{x}}=\int 5t\,dt

Formulae Used:

\int \frac{1}{\sqrt{x}}=2\sqrt{x}\,\,,\,\,\int t\,dt=\frac{t^2}{2}

So, we get solution as 2\sqrt{x}=\frac{5t^2}{2}+C

Applying condition: x(0) = 1, we get C=2

Therefore, 2\sqrt{x}=\frac{5t^2}{2}+2

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Your friend Mel says he has an easier way to solve this problem. Here are the first steps in his method.
damaskus [11]

Simplifying

2x2 + 6x + 4 = 24

Reorder the terms:

4 + 6x + 2x2 = 24

Solving

4 + 6x + 2x2 = 24

Solving for variable 'x'.

Reorder the terms:

4 + -24 + 6x + 2x2 = 24 + -24

Combine like terms: 4 + -24 = -20

-20 + 6x + 2x2 = 24 + -24

Combine like terms: 24 + -24 = 0

-20 + 6x + 2x2 = 0

Factor out the Greatest Common Factor (GCF), '2'.

2(-10 + 3x + x2) = 0

Factor a trinomial.

2((-5 + -1x)(2 + -1x)) = 0

Ignore the factor 2.

Subproblem 1

Set the factor '(-5 + -1x)' equal to zero and attempt to solve:

Simplifying

-5 + -1x = 0

Solving

-5 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '5' to each side of the equation.

-5 + 5 + -1x = 0 + 5

Combine like terms: -5 + 5 = 0

0 + -1x = 0 + 5

-1x = 0 + 5

Combine like terms: 0 + 5 = 5

-1x = 5

Divide each side by '-1'.

x = -5

Simplifying

x = -5

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Step-by-step explanation:

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Answer:

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solving steps:

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