X+y=8
multiply the first equation by 3 to get rid of x
3x+3y=24
3x+2y=14
subtract equation 1 from 2
y=10
substitute to find the value of x
x+10=8
x=-2
m∠AOC = m∠AOB + m∠BOC
We have m∠AOC = 19°, m∠AOB = 4x - 15 and m∠BOC = 2x + 10. Substitute:
19 = (4x - 15) + (2x + 10)
19 = (4x + 2x) + (-15 + 10)
19 = 6x - 5 <em>add 5 to both sides</em>
24 = 6x <em>divide both sides by 6</em>
4 = x
m∠BOC = 2x + 10 → m∠BOC = 2(4) + 10 = 8 + 10 = 18
m∠AOB = 4x - 15 → m∠AOB = 4(4) - 15 = 16 - 15 = 1
<h3>Answer: c. m∠BOC = 18°, m∠AOB = 1°</h3>
The answer is <span>C. 4/5 - 3/5 i
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Answer:
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Step-by-step explanation:
POINTS :D <3