The revenue, in thousands of dollars, of a new flavor of liquor is given below as function of the number of gallons (in hundreds
), x, sold:
What is the maximum revenue? Use units
1 answer:
Answer:
$625,000
Step-by-step explanation:
The maximum revenue will be found where the derivative of the revenue function is zero.
r'(x) = 50 -2x = 0
50 = 2x
x = 25
When 2500 gallons are sold, the revenue is ...
r(25) = 50(25) -25(25) = (50 -25)(25) = 25(25) = 625 . . . thousands
The maximum revenue is $625,000.
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2/9 is the answer hope it will help
20 degrees. i have a protractor, and its really helpful! you should use one.
Answer:
368 cans.
Step-by-step explanation:
Volume of 1 can = π r^2 h.
Here h (height) = 12 and r (radius) = 1/2 * 6 = 3 cm.
So V = π * 3^2 * 12
= 108π cm^3.
The tank hold 125 liters
= 125,000 cm^3, so:
Number of cans that could be filled = 125000/ 108 π
= 368.4.
Answer:
c = $5,400
Step-by-step explanation:
Given:
c = 0.9s
where,
s = amount sold
c = commission on sales
How much commission will he or she earn if the amount sold is $6,000?
Find c when she = $6,000
c = 0.9s
= 0.9 × 6,000
= 5,400
c = $5,400
(c, s) (5400, 6000)
Answer:
9.09 , 0.9 , 0.09 , 0.009 , 0.0009
Explanation:
The more places behind a decimal point a number is, the smaller it is
Hope this helped you! :)
