Question

The revenue, in thousands of dollars, of a new flavor of liquor is given below as function of the number of gallons (in hundreds), x, sold:
$r(x) = 50x - {x}^{2}$
What is the maximum revenue? Use units​

Answer 1

Answer:

  $625,000

Step-by-step explanation:

The maximum revenue will be found where the derivative of the revenue function is zero.

  r'(x) = 50 -2x = 0

  50 = 2x

  x = 25

When 2500 gallons are sold, the revenue is ...

  r(25) = 50(25) -25(25) = (50 -25)(25) = 25(25) = 625 . . . thousands

The maximum revenue is $625,000.