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4 years ago

What are the 5 things needed to make a box plot?

2 answers:

8 0

Box-and-whisker plots and the five key values used in constructing a box-and-whisker plot. The key values are called a five-number summary, which consists of the minimum, first quartile, median, third quartile, and maximum.

castortr0y [4]4 years ago

8 0

Answer:

The five things you need are low extreme, high extreme, median, interquartile 1, and interquartile 3

Step-by-step explanation:

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P is 9 more than half of q

posledela

I hope this helps you

P=q/2+9

8 0

3 years ago

What is the radius of this circle?

Blababa [14]

Answer:

9in

Step-by-step explanation:

radius is half the diameter

18/2 is 9 so the radius is 9in

3 0

3 years ago

Assume that f(x)=ln(1+x) is the given function and that Pn represents the nth Taylor Polynomial centered at x=0. Find the least

WINSTONCH [101]

Answer:

the least integer for n is 2

Step-by-step explanation:

We are given;

f(x) = ln(1+x)

centered at x=0

Pn(0.2)

Error < 0.01

We will use the format;

[[Max(f^(n+1) (c))]/(n + 1)!] × 0.2^(n+1) < 0.01

So;

f(x) = ln(1+x)

First derivative: f'(x) = 1/(x + 1) < 0! = 1

2nd derivative: f"(x) = -1/(x + 1)² < 1! = 1

3rd derivative: f"'(x) = 2/(x + 1)³ < 2! = 2

4th derivative: f""(x) = -6/(x + 1)⁴ < 3! = 6

This follows that;

Max|f^(n+1) (c)| < n!

Thus, error is;

(n!/(n + 1)!) × 0.2^(n + 1) < 0.01

This gives;

(1/(n + 1)) × 0.2^(n + 1) < 0.01

Let's try n = 1

(1/(1 + 1)) × 0.2^(1 + 1) = 0.02

This is greater than 0.01 and so it will not work.

Let's try n = 2

(1/(2 + 1)) × 0.2^(2 + 1) = 0.00267

This is less than 0.01.

So,the least integer for n is 2

7 0

4 years ago

Diego is 59.5 inches tall. His brother is 40.125 inches tall. How much taller than his his brother is Diego?

lukranit [14]

He is 1 inch. Taller

6 0

3 years ago

Find the length of a diagonal of a square with sides 10in. long

Ghella [55]

Hey!!!
Answer is....
diagonals of square bisect each other at right angles.
let diagonal be 2x
Using Pythagoras in a triangle enclosed by a side and 2 half diagonals...
${x}^{2} + {x}^{2} = {10}^{2}$
$2 {x}^{2} = 100$
${x }^{2} = 50$
$x = \sqrt{50}$
side of a diagonal=2 sqrt50
$= 10 \sqrt{2}$
cm......

HOPE IT HELPS YOU '_'

3 0

3 years ago

Read 2 more answers