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Ipatiy [6.2K]
4 years ago
5

Randall bought half pound of American cheese. He used one tenth pound to make a sandwich. How many pounds of cheese did he have

left?
Mathematics
1 answer:
Talja [164]4 years ago
4 0

Answer:

Step-by-step explanation:

He’s black

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How to find the perimeter of a triangle
Alecsey [184]

Answer:

Analyze then add

Step-by-step explanation:

Basically, just analyze the lengths of the sides, and then add them together for the perimeter

Thank me later :)

4 0
4 years ago
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A rectangular lawn has a diagonal path running across it. The lawn is 10m wide and 15m long. Work out the length of the path
Kisachek [45]

Answer:

d = 18.02 m

Step-by-step explanation:

Given that,

A rectangular lawn has a diagonal path running across it. The lawn is 10m wide and 15m long.

We need to find the length of the path.

The diagonal of a rectangle can be calculated as follows :

d=\sqrt{10^2+15^2} \\\\d=18.02\ m

So, the length of the path is 18.02 m.

5 0
3 years ago
The quality assurance engineer of a receiving-sets manufacturer inspects receiving-sets in lots of 50. He selects 4 of the 50 re
Mariana [72]

Answer:

0.0430 = 4.30% probability that exactly 2 of the 4 receiving-sets selected by the engineer are defective.

Step-by-step explanation:

Sets are chosen from the sample without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

Lots of 50 means that N = 50

5 are defective, which means that k = 5

4 are selected, which means that n = 4

Find the probability that exactly 2 of the 4 receiving-sets selected by the engineer are defective.

This is P(X = 2). So

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 2) = h(2,50,4,5) = \frac{C_{5,2}*C_{45,2}}{C_{50,4}} = 0.0430

0.0430 = 4.30% probability that exactly 2 of the 4 receiving-sets selected by the engineer are defective.

4 0
3 years ago
Please answer I’ll make you brainlienst!!
Alecsey [184]

Answer:

4

Step-by-step explanation:

8(-1)^4 - 3(-1) - 7

= 8(1)+3-7

=8+3-7

=4

8 0
3 years ago
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Find the distance between the ordered pairs. (6, 4) and (-3, 4)​
seropon [69]

Answer: = 9

There is really no steps for this answer...

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3 years ago
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