Answers:
- Part A) There is one pair of parallel sides
- Part B) (-3, -5/2) and (-1/2, 5/2)
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Explanation:
Part A
By definition, a trapezoid has exactly one pair of parallel sides. The other opposite sides aren't parallel. In this case, we'd need to prove that PQ is parallel to RS by seeing if the slopes are the same or not. Parallel lines have equal slopes.
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Part B
The midsegment has both endpoints as the midpoints of the non-parallel sides.
The midpoint of segment PS is found by adding the corresponding coordinates and dividing by 2.
x coord = (x1+x2)/2 = (-4+(-2))/2 = -6/2 = -3
y coord = (y1+y2)/2 = (-1+(-4))/2 = -5/2
The midpoint of segment PS is (-3, -5/2)
Repeat those steps to find the midpoint of QR
x coord = (x1+x2)/2 = (-2+1)/2 = -1/2
y coord = (x1+x2)/2 = (3+2)/2 = 5/2
The midpoint of QR is (-1/2, 5/2)
Join these midpoints up to form the midsegment. The midsegment is parallel to PQ and RS.
The value of the derivative of functions h'(6) as requested in the task content is; 55.
<h3>What is the value of h'(6)?</h3>
Since it follows from the task content that the function h(x)=4f(x)+5g(x)+1.
Hence, the derivative of h(x) can be evaluated as;
h'(x)=4f'(x)+5g'(x)
On this note, by substitution, it follows that;
h'(6)=4(5)+5(7)
h'(6) = 55.
Read more on functions;
brainly.com/question/6561461
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Answer:
3) 5
4) 8.2
5) 6.8
6)FG = 6.4
7) EF = 3.6
8)DF = 4.8
Step-by-step explanation:
From the attached triangle, using trigonometric ratio we can find ∠G as; tan^(-1) (6/8)
Thus, ∠G = 36.87°
Still using trigonometric ratios;
FG/8 = cos 36.87°
FG = 8 cos 36.87°
FG = 6.4
3) EF + FG = EG
Since EG is 10, mean of EF and FG = 10/2 = 5
4) mean of EG and FG = (10 + 6.4)/2 = 8.2
5) EF + FG = EG
Thus; EF = EG - FG
EF = 10 - 6.4
EF = 3.6
Mean of EG and EF = (10 + 3.6)/2 = 6.8
6) FG = 6.4
7) EF = 3.6
8) Using trigonometric ratio;
DF/8 = sin 36.87
DF = 8 × 0.6
DF = 4.8
Answer:
6/8 = n/12
Step-by-step explanation:
hope it helps ;)))))))]))))
Answer:
Step-by-step explanation:
(-5) * (-3) * (-3) = -5 * -3 * -3 = 15 * -3 = -45
