All categories

3 years ago

What is the slope of a line that is perpendicular to the line y = x + 5?

Mathematics

2 answers:

Tanzania [10]3 years ago

7 0

Answer:

-1

Step-by-step explanation:

the line is exactly opposite like a mirror image when it is perpendicular,

so the gradient of the first line is 1 (because there is no number beside x, the gradient would be 1), that means the opposite of 1 would be -1.

The answer is -1

Lelu [443]3 years ago

5 0

Answer:

-1.

Step-by-step explanation:

The standard form of a line can be written y = mx + b where m is the slope.

y = x + 5 can be written as y = 1x + 5 which shows that the slope is 1.

If the slope of a line is m then the slope of a line perpendicular to it is -1/m.

So the required slope is -1/1 = -1.

You might be interested in

NEED HELP ASAP PLEASE! WITH BOTH QUESTIONS #10 and #11!

natali 33 [55]

Answer:

The answer for 10 is y= -4x+2

If the slope is exactly the same but the y intercept is different then it will be parallel

The answer for 11 is y-5=-3/2 (x-1)

Step-by-step explanation:

4 0

3 years ago

29. Write iſ as an improper fraction, and multiply the

Alex Ar [27]

Answer: 29 = 5/6

Step-by-step explanation:

first you would convert 1 2/3 into a improper faction. So you would multiply 1 and 3 then add 2 so 5/3 then multiply that by 1/2. You would multiply the numerators and denominators, so 5 times 1 and 3 times 2 which gives you 5/6.

4 0

2 years ago

Solve.<br> x^2+9x+2=0<br> thanks!

shtirl [24]

Step one:
ALWAYS set equation equal to zero, which in this case has already been done for us.

Step two:
Figure out what formula you need to use in order to solve in this case I'd use the Quadratic formula.

a=1
b=9
c=2

Quadratic formula:
$x = \frac{ - b + - \sqrt{(b) ^{2} - 4(a)(c)} }{2(a)}$
Then you would plug in the information.
$x = \frac{ - 9+ - \sqrt{(9) {}^{2} - 4(1)(2) } }{2(1)}$
The solve for what is underneath the square root ONLY.
$x = \frac{ - 9 + - \sqrt{73} }{2}$
Since you cannot solve this any further, your final two answers are...
$x = \frac{ - 9 + \sqrt{73} }{2}$
$x = \frac{ - 9 - \sqrt{73} }{2}$

3 0

3 years ago

What is the perimeter of a polygon with vertices at (−2, 1) , (−2, 4) , (2, 7) , (6, 4) , and (6, 1) ?

alekssr [168]

First we need the distances of the sides of the polygon, because perimeter = sum of all sides.
$d = \sqrt{{(y2 - y1)}^{2} + {(x2 - x1)}^{2} }$
$d1 = \sqrt{{(1 - 4)}^{2} + {( - 2 - - 2)}^{2} } \\ = \sqrt{{(- 3)}^{2} + {(0)}^{2} } = \sqrt{9} \: = 3$
$d2 = \sqrt{{(4 - 7)}^{2} + {( - 2 - 2)}^{2} } \\ = \sqrt{{(- 3)}^{2} + {( -4)}^{2} } = \sqrt{9 + 16} \\ = \sqrt{25} \: = 5$
$d3 \: = \sqrt{{(7 - 4)}^{2} + {(2 - 6)}^{2} } \\ = \sqrt{{(3)}^{2} + {( - 4)}^{2} } = \sqrt{9 + 16} \\ = \sqrt{25} \: = 5$
$d4 = \sqrt{{(4 - 1)}^{2} + {(6 - 6)}^{2} } \\ = \sqrt{ {(3)}^{2} + {(0)}^{2} } = \sqrt{9} \: = 3$
$d5 = \sqrt{{(1 - 1)}^{2} + {(-2 - 6)}^{2} } \\ = \sqrt{ {(0)}^{2} + {( - 4)}^{2}} = \sqrt{16} \: = 4$
Now, we add all sides for the perimeter:
p = d1 + d2 + d3 + d4 + d5
p = 3+5+5+3+4 = 20 units

5 0

3 years ago

Read 2 more answers

Plzzzzz answer need it plzzz I say

dexar [7]

Answer:

360 square inches

Step-by-step explanation:

12*15 = 360

7 0

3 years ago

Read 2 more answers