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marshall27 [118]
2 years ago
7

Which statements are true about the rules of multiplication for signed numbers? Check all that apply.

Mathematics
2 answers:
weqwewe [10]2 years ago
7 0

Answer:

here I think this is the same question. Hop this helps!

galina1969 [7]2 years ago
6 0

The product of two negative integers is positive. (-a) *(-b) = ab  True

The product of two integers with different signs is positive. (-a) (b) = -ab  False

If two numbers are the same sign, then the product is positive.

a*b = ab   -a * -b = ab   True

The product of a positive and a negative is negative.

-a * b =- ab    a * -b =- ab      True

If the signs of two integers are different, then the product is positive.

-a * b =- ab    a * -b =- ab      False


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Evaluate the expression and write your answer in the form a + bi. 1) (2-6i)+(4+2i)2) (6+5i)(9-2i)3) 2/(3-9i)4) (3 − 5i)(7 − 2i)
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Step-by-step explanation:

Given the following complex numbers, we are to expressed them in the form of a+bi where a is the real part and b is the imaginary part of the complex number.

1) (2-6i)+(4+2i)

open the parenthesis

= 2-6i+4+2i

collect like terms

= 2+4-6i+2i

= 6-4i

2)  (6+5i)(9-2i)

= 6(9)-6(2i)+9(5i)-5i(2i)

= 54-12i+45i-10i²

= 54+33i-10i²

In complex number i² = -1

= 54+33i-10(-1)

= 54+33i+10

= 54+10+33i

= 64+33i

3) For the complex number 2/(3-9i), we will rationalize by multiplying by the conjugate of the denominator i.e 3+9i

= 2/3-9i*3+9i/3+9i

=2(3+9i)/(3-9i)(3+9i)

= 6+18i/9-27i+27i-81i²

= 6+18i/9-81(-1)

= 6+18i/9+81

= 6+18i/90

= 6/90 + 18i/90

= 1/15+1/5 i

4) For (3 − 5i)(7 − 2i)

open the parenthesis

= 3(7)-3(2i)-7(5i)-5i(-2i)

= 21-6i-35i+10i²

= 21-6i-35i+10(-1)

= 21-41i-10

= 11-41i

4 0
3 years ago
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