Answer:
21.62m
Step-by-step explanation:
first draw the the pipe
second you need know wich is the angle between the pipe and the corner
β=Tan^-1(6/9)=33.7
find the components using tow triangles
a=9/cos(33.7)=10.81m
b=6/sen(33.7)=10.81m
finally sum the leghts
L=10.81+10.81=21.62mm
attached procedure
the value for f(5.3)=6×5.3
=31.8
x-32.2= 18.5
Add 32.2 to both sides
x-32.2+32.2 = 18.5 + 32.2
x = 50.7
I hope that's help !
Check your answer
replace x by its number
50.7-32.2= 18.5
18.5 = 18.5
so the answer is good .
Please let me know if you have question(s) !
Answer:
t = 5/2
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
3t + 7 = 2 + 5t
<u>Step 2: Solve for </u><u><em>t</em></u>
- [Subtraction Property of Equality] Isolate <em>t</em> terms: 7 = 2 + 2t
- [Subtraction Property of Equality] Isolate <em>t</em> term: 5 = 2t
- [Division Property of Equality] Isolate <em>t</em>: 5/2 = t
- Rewrite: t = 5/2
Answer:
The amount of Polonium-210 left in his body after 72 days is 6.937 μg.
Step-by-step explanation:
The decay rate of Polonium-210 is the following:
(1)
Where:
N(t) is the quantity of Po-210 at time t =?
N₀ is the initial quantity of Po-210 = 10 μg
λ is the decay constant
t is the time = 72 d
The decay rate is 0.502%, hence the quantity that still remains in Alexander is 99.498%.
First, we need to find the decay constant:
(2)
Where t(1/2) is the half-life of Po-210 = 138.376 days
By entering equation (2) into (1) we have:
Therefore, the amount of Polonium-210 left in his body after 72 days is 6.937 μg.
I hope it helps you!