Answer:
21.62m
Step-by-step explanation:
first draw the the pipe
second you need know wich is the angle between the pipe and the corner
β=Tan^-1(6/9)=33.7
find the components using tow triangles
a=9/cos(33.7)=10.81m
b=6/sen(33.7)=10.81m
finally sum the leghts
L=10.81+10.81=21.62mm
attached procedure
Answer:
The amount of Polonium-210 left in his body after 72 days is 6.937 μg.
Step-by-step explanation:
The decay rate of Polonium-210 is the following:
(1)
Where:
N(t) is the quantity of Po-210 at time t =?
N₀ is the initial quantity of Po-210 = 10 μg
λ is the decay constant
t is the time = 72 d
The decay rate is 0.502%, hence the quantity that still remains in Alexander is 99.498%.
First, we need to find the decay constant:
(2)
Where t(1/2) is the half-life of Po-210 = 138.376 days
By entering equation (2) into (1) we have:
Therefore, the amount of Polonium-210 left in his body after 72 days is 6.937 μg.
I hope it helps you!