Answer:
The maximum amount of money the chemistry club can spend without going over their buget is $81.4 ... With a total of 6 hours their allowed to use the room for.
Step-by-step explanation:
$49 is our constant and will not change. 5.40 however will. Let's use variable h for the amount hours they can rent the room for. Now we can make an inequality;
49+ 5.40h < 86.80
5.40h < 86.80
5.4h< 37.8
h< 7
Now that we know h will have to be less than seven for the chemistry club to spend less than their buget we can find that 6 is the maxium amount of hours they can spend in the room while staying within their budget.
(This answer does not consider decimals or half hours)
Answer:
Step-by-step explanation:
<u>Given function</u>
<u>To find</u>
<u>Solution</u>
Substitute x with 3 in the equation to find f(3)
- f(3) = -4(3+3) = -4*6 = -24
Answer: Bob has 62 cards.
All has 124 cards.
Jane has 186 cards
Step-by-step explanation:
Let x represent the number of cards that Bob has.
Al has twice as many cards as Bob. It means that the number of cards that All has is 2x.
Jane has three times as many cards as Bob. It means that the number of cards that Jane has is 3x.
Together, they have 372 cards. It means that
x + 2x + 3x = 372
6x = 372
x = 372/6
x = 62
The number of cards that Al has is
2 × 62 = 124
The number of cards that Jane has is
3 × 62 = 186
