Answer:
Simplify
A ⋅ 13−oz.
−oz+13 A
Simplify
a⋅20+0z.
20a
List all of the solutions.
A⋅13−oz=−oz+13A 78=−oz+13a⋅20
Well you need first 1 2/4 of a yard. Then you will need 5/6 of a yard. But first you need to put them together. So we need to find the common denominator. Six and four both share which multiple? Twelve. So let's rewrite that. You need 1 6/12 yards + 10/12 yards of wrapping paper. But before we do anything else we need to fix the mixed number. 1 6/12 isn't as easy to add ad 18/12 is. So 18/12 + 10/12 = 28/12
That can simplify as well. Now it's 14/6 which is equivalent to the fraction we had before. But it can also go down to 2 2/6. Now we can simplify it even further. By dividing it by two we can get 2 1/3. These are the measurements we need. So you would need how many thirds? Seven. (2 1/3 is seven thirds) This is your final answer.
You would need to have seven peices of wrapping paper cut to wrap both gift boxes.
To solve this problem you must apply the proccedure shown below:
1. You have to find the radius <span>of convergence of the following Maclaurin series:
</span>
2. Let's take the denominator and find the roots:
3. The roots are
and the distance from the origin is
.
Therefore, the answer is:
Answer:x>-1
Step-by-step explanation:
The vertical asymptote is r = 0. The intensity is undefined at the source. The horizontal asymptote is I = 0. As the distance from the source increases, the intensity goes to zero. The intensity decreases as the distance increases.
