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VMariaS [17]
4 years ago
14

6g=48 g=? Please hell

Mathematics
2 answers:
Sladkaya [172]4 years ago
8 0

Answer:

g = 8

Step-by-step explanation:

We're going to isolate g to find out what it equals, so we have to divide both sides by 6.

6g=48

__   __

6     6

g = 8

cupoosta [38]4 years ago
4 0

Answer:

G=8

Step-by-step explanation:

Can i get brainliest?

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Find the perimeter of a quadrilateral with vertices at C (-1, 2), D (-2, -1), E (2, -2), and F (1, 1). Round your answer to the
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Answer:

B 12.68

Step-by-step explanation:

you will need to find the distance between each segment-

so the length of DC, CF, FE, ED

d=\sqrt{(x_{2}-x_{1})  ^{2}+(y_{2}-y_{1})  ^{2}  }

DC:

D(-2,-1) C(-1,2)

d=\sqrt{(-1--2)^{2} +(2--1)^{2} } \\d=\sqrt{1^{2}+3^{2}  } \\d=\sqrt{10} =3.16

CF:

C(-1,2) F(1,1)

d=\sqrt{(1--1)^{2} +(1-2)^{2} } \\d=\sqrt{2^{2}+-1^{2}  } \\d=\sqrt{4+1} \\d=\sqrt{x} 5=2.24

FE

F(1,1) E(2,-2)

d=\sqrt{(2-1)^{2} +(-2-1)^{2} } \\d=\sqrt{1^{2} +(-3)^{2} } \\d=\sqrt{1+9} \\d=\sqrt{10}= 3.16

ED

E(2,-2) D(-2,-1)

d=\sqrt{(-2-2)^{2} +(-1--2)^{2} } \\d=\sqrt{(-4)^{2}+1^{2}  } \\d=\sqrt{16+1} \\d=\sqrt{17}= 4.12\\

3.16+2.24+3.16+4.12= 12.68

4 0
3 years ago
Find one counter example to show that the conjecture is false. angle 1 and angle 2 are​ supplementary, so one of the angles is a
Mrac [35]

Answer:

B. m ∠ 1 = 90° and m ∠ 2 = 90°

Step-by-step explanation:

For most situations, the conjecture would probably be true, but there is one exception that makes this statement false.

When two right angles are supplementary, none of them is acute.

For an angle to be acute it needs to be lesser than 90°, and for a pair of angles to be supplementary they should add up to exactly 180°.

With a pair of right angles (90° each), their sum adds up to 180° but neither of them are acute.

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4 years ago
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jeka57 [31]

Answer:

I believe it would be y-3=23x-2

7 0
3 years ago
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tatuchka [14]
8 strawberries : 32 strawberries
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3 years ago
Solve the following system of linear equations by graphing.
Oksanka [162]

Answer:

See Explanation

Step-by-step explanation:

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