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4 years ago

Find two consecutive odd integers whose sum is 168. PLEASE HELP!

2 answers:

8 0

Ok so first you want to start off by defining the first number as x. Little tip: a consecutive ODD number will be two apart for the previous odd number. So it would be something like x + 2, x + 4 and so on.

So in this case I would make a key that would look something like this:

1: x
2:x+2

Now we need an equation. We now we need to add number 1 and number two so our equation, would be 2x + 2=168. Then you solve from there.

If you need help with solving this equation you can meeage me!

sleet_krkn [62]4 years ago

4 0

The answer is 12 and 14

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Which fraction has a repeating decimal as its decimal expansion?

Kobotan [32]

Answer:

Step-by-step explanation:

a=0.15789474

b=0.1875

c=0.27272727

d=0.375

7 0

3 years ago

Read 2 more answers

A large storage tank, open to the atmosphere at the top and filled with water, develops a small hole in its side at a point 10.4

vlabodo [156]

Answer:

Therefore the diameter of the hole is $1.94 \times 10^{-3}$ m.

Step-by-step explanation:

Bernoulli's equation,

$P_1+\frac12 \rho v^2_1+\rho g h_1= P_2+\frac12 \rho v^2_2+\rho g h_2$

P₁ = P₂= atmospheric presser

$\rho$ = density

$\frac12 \rho v^2_1+\rho g h_1= \frac12 \rho v^2_2+\rho g h_2$ [since P₁ = P₂]

$\Rightarrow\rho (\frac12 v^2_1+ g h_1)= \rho(\frac12 v^2_2+ g h_2)$

$\Rightarrow\frac12 v^2_1+ g h_1= \frac12 v^2_2+ g h_2$

$\Rightarrow\frac12 v^2_2-\frac12 v^2_1=g h_1- g h_2$

$\Rightarrow v^2_2- v^2_1=2g h$ [ $h_1-h_2=h$ ]

Here $v_1\approx 0$

$\Rightarrow v^2_2=2g h$

$\therefore v_2=\sqrt {2gh$

Here g= 9.8 m/s² , h = 10.4 m

The velocity of water that leaves from the hole $v_2$ = $\sqrt {2\times 9.8\times 10.4}$ m/s

=14.28 m/s.

Given, the rate of flow from the leak is $2.53\times 10^{-3}$ $m^3/min$

$=\frac{2.53\times 10^{-3}}{60}$ $m^3/s$

Let the diameter of the hole be d.

Then the cross section area of the hole is $=\pi (\frac d2)^2$

We know that,

The rate of flow = Cross section area × speed

$\Rightarrow \frac{2.53\times 10^{-3}}{60} =\pi (\frac d2)^2\times 14.28$

$\Rightarrow (\frac d2)^2=\frac{2.53\times 10^{-3}}{60\times 14.28\times \pi}$

$\Rightarrow d= 1.94 \times 10^{-3}$

Therefore the diameter of the hole is $1.94 \times 10^{-3}$ m.

4 0

4 years ago

I'd appreciate it if anyone could help ASAP! :) I'll give Brainliest!

sergiy2304 [10]

We have been given a graph of function g(x) which is a transformation of the function $f(x)=3^x$

Now we have to find the equation of g(x)

Usually transformation involves shifting or stretching so we can use the graph to identify the transformation.

First you should check the graph of $f(x)=3^x$

You will notice that it is always above x-axis (equation is x=0). Because x-axis acts as horizontal asymptote.

Now the given graph has asymptote at x=-2

which is just 2 unit down from the original asymptote x=0

so that means we need shift f(x), 2 unit down hence we get:

$y=3^x$

but that will disturb the y-intercept (0,1)

if we multiply $3^x$ by 3 again then the y-intercept will remain (0,1)

Hence final equation for g(x) will be:

$g(x)=3(3^x)-2$

5 0

3 years ago

In the function f(x) = 4(x2 − 6x + ____) + 20, what number belongs in the blank to complete the square?

grandymaker [24]

The right answer for the question that is being asked and shown above is that: In the function f(x) = 4(x2 − 6x + ____) + 20, what number belongs in the blank to complete the square?

x2 - 6x + 9

So the answer on the blank space is 9. It should be a perfect square.
= 6/2
= 3^2
= 9

5 0

3 years ago

PLZ NEED HELP DUE TONIGHT

coldgirl [10]

Answer:

-10 and -2/5

Step-by-step explanation

-10÷ $-\frac{2}{5}$ = 25

Check

25 > 10

5 0

3 years ago