Answer:
a.27
Step-by-step explanation:
Using Pythagoras theorem:
x=sqrt(6^2+26^2)
x=26.683..
By rounding, x=27
Answer:
x ≤ 6 and x ≥ 2
Step-by-step explanation:
For now, we will start with doing each problem at a time. Here is your equation:
2x - 4 ≤ 8
First, you want to get the variable by itself. So, you add 4 to both sides. It will look like this:
2x - 4 ≤ 8
+ 4 + 4
The four being added on the left side cancels out, and you add 4 to 8. Now, it should look like this:
2x ≤ 12
Next, you want the x by itself. So, you would divide both sides by 2.
2x ≤ 12
/2 /2
2 divided by 2 cancels out, and 12 divided by 2 equals 6. Now, you have a final answer of:
x ≤ 6
But, you now have to do the other one!
Here is what you start off with:
x + 5 ≥ 7
First, you want the variable side by itself. So, you subtract 5 from both sides.
x + 5 ≥ 7
- 5 -5
Now, you have this:
x ≥ 2
Because the variable is already by itself, you don't need to do any more division and this is you final answer. Now put both answers you got together which equals:
x ≤ 6 and x ≥ 2
Answer:
rectagle
Step-by-step explanation:
Here we're applying a basic physics rule for vertical motion where the only pull on the object is gravity.
This rule has the form
h(t) = h + v t + (1/2)a*t^2
o o
To adapt this rule to this particular question replace h with 0, as the
o
upward path of the object begins at 0 ft. Replace v with +15 ft/sec.
o
Replace "a" with (-32.2 ft/(sec^2); this is the acceleration due to gravity.
Then we have the following, with the label F(t):
F(t) = 0 + (15 ft/sec)t + (1/2)(-32.2 ft)/(sec^2), or
F(t) = 15t - 16.1t^2. Thus, Choice D is correct.
Please note: To avoid confusion, please use " ^ " to denote exponentiation:
F(t) = -16t^2 + 15t
Answer:
Step-by-step explanation:
<u>Sample Space</u>
The sample space of a random experience is a set of all the possible outcomes of that experience. It's usually denoted by the letter 
.
We have a number cube with all faces labeled from 1 to 6. That cube is to be rolled once. The visible number shown in the cube is recorded as the outcome. The possible outcomes are listed as the sample space below:
Now we are required to give the outcomes for the event of rolling a number less than 5. Let's call A to such event. The set of possible outcomes for A has all the numbers from 1 to 4 as follows
