What's the question you're asking?
Answer:
5 length
Step-by-step explanation:
The diagram attached shows two equilateral triangles ABC & CDE. Since both squares share one side of the square BDFH of length 10, then their lengths will be 5 each. To obtain the largest square inscribed inside the original square BDFH, it makes sense to draw two other equilateral triangles AGH & EFG at the upper part of BDFH with length equal to 5.
So, the largest square that can be inscribe in the space outside the two equilateral triangles ABC & CDE and within BDFH is the square ACEG.
The area of the following shape is 50
Answer:
B and E
Step-by-step explanation:
Answer:
The answer is A
Step-by-step explanation:
If you plug in the numbers it looks like this:
(A) 5(2) + 10(5) = 60
(B) 10(2) + 5(5) = 45
(C) 7(2) + 8(5) = 54
(D) 8(2) + 7(5)
so a is the only one that equals 60