Step-by-step explanation:
The volume of the cone is:
1/3 *π* r² *h =
1/3 *π *4* 2square root of 3=
(8*square root of 3*π)/3
Answer:
72 square units
Step-by-step explanation:
- Identify the height
- Identify the length
- Multiply those two together
- That is your answer
H = 9 units
L = 8 units
A = H × L
A = 9 × 8
A = 72 square units
Write the equation of the first train: x = 12t
Write the equation of the second train: y = -20t+72, assuming the train one is at the origins when t = 0.
Now solve the equation: 12t=-20t+72,
32t = 72, then t = 2.25 hours. The two train meet after 2.25 hours.
Now the equation of the <span>pigeon is like this: x = 48t.
</span>Then for t = 2.25, we get

<span>
The Hyde has flown 108 km when the trains meet.</span>
Answer:
<u>At a constant speed of 0.5 miles per minute, the ostrich can run 20 miles in 40 minutes. The unit rate is 0.5 miles per minute.</u>
Step-by-step explanation:
Distance run by the ostrich = 6 miles
Time the ostrich takes to run this distance = 12 minutes
Speed of the ostrich = Distance / Time
Speed of the ostrich = 6 miles / 12 minutes = 0.5 miles per minute
How far the ostrich could run in 40 minutes?
If the ostrich run 0.5 miles per minute, this is the formula:
Speed of the ostrich * 40 minutes = Distance
0.5 miles/minute * 40 minutes = 20 miles (Minutes is simplified in the numerator and the denominator on the left side)
<u>At a constant speed of 0.5 miles per minute, the ostrich can run 20 miles in 40 minutes. The unit rate is 0.5 miles per minute.</u>
Answer:
Step-by-step explanation:
As per Janayda,
From the figure attached,
In ΔTRQ,
m∠TRQ + m∠RQT + m∠QTR = 180°
25° + m∠RQT + 35° = 180°
m∠RQT = 180° - 60°
m∠RQT = 120°
Since, m∠RQT + m∠PQT = 180° [Linear pair of angles]
m∠PQT = 180° - m∠RQT
= 180° - 120°
= 60°
In right angled triangle TPQ,
m∠TPQ + m∠PQT + m∠PTQ = 180°
90° + 60° + m∠PTQ = 180°
m∠PTQ = 180° - 150°
= 30°
Similarly, other angles can also be evaluated from the given information.
In ΔQTP and ΔNTP,
TP ≅ TP [Reflexive property]
NP ≅ PQ [Given]
ΔQTP ≅ ΔNTP [By LL postulate for congruence]
Therefore, Janayda is correct.
While Sirr is incorrect.
Since, there is not the enough information to prove ΔRTQ and ΔMTN equal, Isabelle is incorrect.