Answer:
Approximately 62.83 inches.
Exactly 20π inches.
Step-by-step explanation:
It's simply the wheel's circumference.
<em>C</em> = 2π<em>r</em> = 2(10)(π) = 20π ≈ 62.83 inches
To solve this problem you must apply the proccedure shown below:
1. You have that the formula for calculate the area of a triangle is:
A=bh/2
Where A is the area of the triangle, b is the base of the triangle and h is the height of the triangle.
bh/2=124
bh=124x2
bh=248
2. The problem asks for the new area of the triangle <span>if its base was half as long and its height was three times as long. Then, you have:
Base=b/2
Height=3h
3. Therefore, when you substitute this into the formula for calculate the area of a triangle, you obtain:
A'=bh/2
(A' is the new area)
A'=(b/2)(3)/2
A'=3bh/4
4. When you substitute bh=248 into </span>A'=3bh/4, you obtain:
<span>
A'=186 units</span>²
<span>
The answer is: </span>186 units²
Answer:
3 + 9i
Step-by-step explanation:
(4 + 2i) - (1 - 7i)
distribute the (-)
(4 + 2i) - 1 + 7i
combine like terms
3 + 9i
Answer:
198 cubic metres
Steps:
<em><u>Find </u></em><em><u>the </u></em><em><u>area </u></em><em><u>of </u></em><em><u> </u></em><em><u>cross</u></em><em><u> </u></em><em><u>section</u></em>
<em><u>Area </u></em><em><u>if </u></em><em><u>traing</u></em><em><u>l</u></em><em><u>e </u></em><em><u>+</u></em><em><u> </u></em><em><u>Area </u></em><em><u>of </u></em><em><u>square</u></em>
<em><u>1</u></em><em><u>/</u></em><em><u>2</u></em><em><u> </u></em><em><u>×</u></em><em><u> </u></em><em><u>3</u></em><em><u> </u></em><em><u>×</u></em><em><u> </u></em><em><u>4</u></em><em><u> </u></em><em><u>+</u></em><em><u> </u></em><em><u>4</u></em><em><u>×</u></em><em><u>4</u></em>
<em><u>6</u></em><em><u>+</u></em><em><u> </u></em><em><u>1</u></em><em><u>6</u></em>
<em><u>2</u></em><em><u>2</u></em>
<em><u>Then </u></em><em><u>times </u></em><em><u>with </u></em><em><u>the </u></em><em><u>lenght </u></em><em><u>(</u></em><em><u>9</u></em><em><u>)</u></em>
<em><u>2</u></em><em><u>2</u></em><em><u>×</u></em><em><u>9</u></em>
I hope this helps, dont hesitate to ask for any question.
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