How many grams of active ingredient F should be used to prepare 135 g of a 6.7% (w/w) solution in water?
1 answer:
Answer:
We need 9.045 grams of active ingredient F to prepare a 6.7% (w/w) solution in water.
Step-by-step explanation:
6.7% (w/w) solution in water can also be expressed as: 6.7 g in 100 g of solution.
Hence:
We have to dilute 9.045 g of active ingredient F until getting 100 g of solution.
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