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3 years ago

Calculate the score percentage if out of 15 shots, 12 are successfull.

Mathematics

1 answer:

schepotkina [342]3 years ago

8 0

80% is the score percentage

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Functions

Illusion [34]

I’m not sure but maybe true

3 0

3 years ago

-2x+5/2= 17

Alenkinab [10]

No the answer is 5x because simply then,add x

3 0

3 years ago

Read 2 more answers

Mr. Scruggs got some money for his birthday. He spent 1/5 of it on dog treats. Then, he divided the remainder equally among his

Mariulka [41]

Answer:

a. $\frac{4a}{15}$

b. $225

Step-by-step explanation:

Let Mr. Scruggs got money for his birthday be 'a'

He spent $\frac{1}{5}$ of it on dog treats = a × $\frac{1}{5}$

= $\frac{1}{5}a$

remainder amount would be = a - $\frac{1}{5}a$

= $\frac{4a}{5}$

Then he divided the remainder money equally among 3 favorite charities.

$\frac{\frac{4a}{5}}{3}$

= $\frac{4a}{15}$

a. Each charity receive $\frac{4a}{15}$

b. If he donated $60 to each charity.

$\frac{4a}{15}=60$

$a=\frac{15\times 60}{4}$

a = $225

Mr. Scruggs received $225 for his birthday.

6 0

3 years ago

Factor the following:<br><br> 1. 5(a+3)²- (a+3<br><br> 2. p²- 6 - q · (p²- 6)²

scoundrel [369]

Answer:

1. $(a + 3)(5a-14)$

2. $(p^2-6)[1-q(p^2-6)]$

Step-by-step explanation:

1. The first thing to do to factor the expression is to take the expression (a + 3) as a common factor with its lowest exponent.

Then the expression. $5(a + 3)^2- (a + 3)$ remains as:

$(a + 3)(5 (a + 3) -1)\\\\(a + 3)(5a +15 -1)\\\\(a + 3)(5a-14)$

2. The first thing to do to factor the expression is to take the expression $p^2 -6$ as its common factor with its lowest exponent.

Then the expression $p^2- 6 - q(p^2- 6)^2$ remains as:

$(p^2-6)[1-q (p^2-6)]$

8 0

3 years ago

In a prior sample of corn, farmer Carl finds that 14% of the sample has worms but the margin of error for his population estimat

Savatey [412]

Answer: 741

Step-by-step explanation:

As per given ,we have

The prior estimate of population proportion: $p=0.14$

Margin or error : 2.5%=0.025

Critical value for 95% confidence = $z_{\alpha/2}=1.96$

Formula to find the sample size :-

$n=p(1-p)(\dfrac{z_{\alpha/2}}{E})^2$

i.e. $n=0.14(1-0.14)(\dfrac{1.96}{0.025})^2$

$=740.045824\approx741$

Hence, the minimum sample size required to obtain this type of accuracy= 741

6 0

3 years ago