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3 years ago

Evaluate 31 + 2x when x = 4.

Mathematics

2 answers:

alexira [117]3 years ago

8 0

It's 39. You multiply 2 and 4 first then you add

Korolek [52]3 years ago

3 0

X=4 so
2x=8
2x4=8
8+31 =39

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Ariana’s annual(year) pay is $34,320. What is her average gross pay?

MArishka [77]

Answer:

9. $2,860 per month

10. $660 per week

11. $94 per day <u><em>(not 100% sure on this one, not sure if its getting techinical with working 5 days a week)</em></u>

Step-by-step explanation:

9. $34,320 divide by number of months in a year (12)

10. $34,320 divide by number of weeks in a year (52)

11. $34,320 divide by number of days in a year (365)

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3 years ago

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Step-by-step explanation:

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3 years ago

Simplify - root (9+y)^2 if y <-10

nevsk [136]

Answer:

− √ ( 9 + y ) 2 > 1

Explanation:

− √ ( 9 + y ) 2 , where y < − 10

Simplify the expression,

− √ ( 9 + y ) 2 = − ( 9 + y ) = − 9 − y

When y < − 10 , − y > 10

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− 9 − y > 1 Hence,

− √ ( 9 + y ) 2 > 1

6 0

3 years ago

In a lab experiment, a student is trying to apply the conservation of momentum. Two identical balls, each with a mass of 1.0 kg.

muminat

Answer:

Trial- 2 shows the conservation of momentum in a closed system.

Step-by-step explanation:

Given: Mass of balls are $m= 1.0\ kg$

Conservation of momentum in a closed system occurs when momentum before collision is equal to momentum after collision.

Let initial velocity of ball $A\ is\ u_1$
Initial velocity of ball $B\ is\ u_2$
Final velocity of ball $A\ is\ v_1$
Final velocity of ball $B\ is\ v_2$
Momentum before collision $= mu_1+mu_2$
Momentum after collision $=mv_1+mv_2$

Now, According to conservation of momentum.

Momentum before collision = Momentum after collision

$mu_1+mu_2=mv_1+mv_2$

We will plug each trial to this equation.

Trial 1

$mu_1+mu_2=mv_1+mv_2\\1.0(1)+1.0(-2)=1.0(-2)+1.0(-1)\\1-2=-2-1\\-1=-3$

Trial 2

$mu_1+mu_2=mv_1+mv_2\\1.0(.5)+1.0(-1.5)=1.0(-.5)+1.0(-\.5)\\.5-1.5=-.5-.5\\-1=-1$

Trial 3

$mu_1+mu_2=mv_1+mv_2\\1.0(2)+1.0(1)=1.0(1)+1.0(-2)\\2+1=1-2\\3=-1$

Trial 4

$mu_1+mu_2=mv_1+mv_2\\1.0(.5)+1.0(-1)=1.0(1.5)+1.0(-1.5)\\.5-1=1.5-1.5\\-.5=0$

We can see only Trial 2 satisfies the princple of conservation of momentum. That is momentum before collison should equal to momentum after collision.

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3 years ago

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jolli1 [7]

Answer: 36

Step-by-step explanation: i do not cap

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3 years ago

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