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barxatty [35]
3 years ago
6

How to write a whole number into a fraction in a subtraction problem

Mathematics
1 answer:
insens350 [35]3 years ago
7 0
Im hoping you just want an example so here you go

whole number: 16
fraction version of 16: 16/1

to subtract fractions you have to have a common denominator.

so if i had a problem like     6 -1/3
step 1 would be to turn 6 into a fraction: 6/1
step 2 is to find the common denominator:
6/1 -1/3, in this case it is 3, so you multuply the first term by 3
you would then get     18/3 - 1/3,  now all you do if subract numerators, 18-3=15

final answer would be 15/3, you can simplify it into 5/1 which is also 5

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7.1 divided by 312.755
RUDIKE [14]

answer 0.0227014756

Step-by-step explanation:

or if you meant 312.775/7.1 it's 44.0528169

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3 years ago
Four friends charge different amounts for babysitting.<br><br> Who charges the most per hour?
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Hi answer as fast as you can
Aleonysh [2.5K]

Answer:

864 cm

Step-by-step explanation:

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3 years ago
The sugar content of the syrup in canned peaches is normally distributed. A random sample of n = 10 cans yields a sample standar
Serggg [28]

Answer:

The 95% confidence interval is given by:

3.30<σ<8.76

Step-by-step explanation:

1) Data given and notation

s=4.798 represent the sample standard deviation

\bar x represent the sample mean

n=10 the sample size

Confidence=95% or 0.95

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .

2) Calculating the confidence interval

The confidence interval for the population variance is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma^2 \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

df=n-1=10-1=9

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a tabel to find the critical values.  

The excel commands would be: "=CHISQ.INV(0.025,9)" "=CHISQ.INV(0.975,9)". so for this case the critical values are:

\chi^2_{\alpha/2}=19.022

\chi^2_{1- \alpha/2}=2.700

And replacing into the formula for the interval we got:

\frac{(9)(4.798)^2}{19.022} \leq \sigma \frac{(9)(4.798)^2}{2.700}

10.892 \leq \sigma^2 \leq 76.736

Now we just take square root on both sides of the interval and we got:

3.30 \leq \sigma \leq 8.76

So the best option would be:

3.30<σ<8.76

7 0
3 years ago
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Answer:

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