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Akimi4 [234]
2 years ago
6

PLZZ HELP NO TIME! HAVE TO SHOW WORK

Mathematics
1 answer:
Rasek [7]2 years ago
6 0
But I want the value of (x) or (y) to complete the solve
I hope that I help you

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I NEED YOUR HELPP !!!
Paladinen [302]

Answer:7 4ts

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Simplify 0.75 (5v+11)-0.25 (11+v)
wariber [46]
<span>2 • (7v + 11) over  4 is your answer :)</span>
5 0
3 years ago
Y is inversely proportional to a^3
Ludmilka [50]

Answer:

y = 0.64/x^3

Step-by-step explanation:

If y is inversely proportional to a^3, we can write the equation:

y * a^3 = k

Using a = 2 and y = 10, we have:

10 * 2^3 = k

k = 80

If a is directly proportional to x, we can write the equation:

a = c * x

Using x = 4 and a = 20, we have:

20 = c * 4

c = 5

Now, using the value of a = 5*x in the equation y * a^3 = 80, we have:

y * (5x)^3 = 80

y * 125x3 = 80

y = 80/(125x3) = 0.64/x^3

6 0
2 years ago
Susan made 2 galons of punch to by divided in 10 persons...how much punch did each person recieve
Hoochie [10]
1 gallon = 128 oz
2 gallons = 256 oz
256/10 = 25.6 oz
each person received 25.6 oz of punch or 3.2 cups
4 0
3 years ago
Determine what must be multiplied so that the expression below will have a common denominator. Use the backslash / to type in a
Mashutka [201]

Answer:

Multiply the first fraction by \frac{x+4}{x+4}

Multiply the second fraction by \frac{x-4}{x-4}

Step-by-step explanation:

Given

\frac{4}{x^2 - 16} + \frac{3}{x^2 + 8x + 16}

Required

Make the denominator equal

\frac{4}{x^2 - 16} + \frac{3}{x^2 + 8x + 16}

Factorize the denominator

\frac{4}{x^2 - 4^2} + \frac{3}{x^2 + 4x + 4x+ 16}

\frac{4}{(x - 4)(x + 4)} + \frac{3}{(x+ 4)(x + 4)}

Multiply the first fraction by \frac{x+4}{x+4}

Multiply the second fraction by \frac{x-4}{x-4}

\frac{x+4}{x+4} * \frac{4}{(x - 4)(x + 4)} + \frac{3}{(x+ 4)(x + 4)} * \frac{x-4}{x-4}

\frac{4(x + 4)}{(x - 4)(x + 4)(x + 4)} + \frac{3(x - 4)}{(x+ 4)(x + 4)(x - 4))}

\frac{4(x + 4)}{(x^2 - 16)(x + 4)} + \frac{3(x - 4)}{(x^2 - 16)(x + 4))}

<em>The expression now have the same denominator</em>

7 0
3 years ago
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