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2 years ago

Matt can buy an 8-ounce jar of salsa $2.79 or a 15-ounce jar of salsa for $5.54. Which jar has the best unit rate

Mathematics

2 answers:

harkovskaia [24]2 years ago

8 0

2.79/8=.34875 per oz
5.54/15=.369333 per oz
Buying the 8 oz jar of salsa would be cheaper.

Talja [164]2 years ago

5 0

8 ounce jar of salsa that's my thought

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What is the length of the shorter base of the Little Trapezoid trail?

valentina_108 [34]

Answer:

The length of the shorter base of the little trapezoid trail is 1 mi.

Step-by-step explanation:

Let the shorter base of the large trapezoid is S and the larger base of the large trapezoid is L.

Similarly, assume that the shorter base of the small trapezoid is s and the larger base of the small trapezoid is l.

Since, the trapezoids are similar, so

$\frac{L}{l} = \frac{S}{s}$

Now, given that S = 2 mi, L = 8 mi and l = 4 mi and we have to find s.

So, $s = \frac{S \times l}{L} = \frac{4 \times 2}{8} = 1$ mi. (Answer)

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2 years ago

What is the perimeter of a triangle with the side lengths 4 cm, 6 cm, and (3y-2) cm?

jek_recluse [69]

Answer:

Step-by-step explanation:

P = 4 + 6 + (3y - 2) Remove the brackets

P = 10 + 3y - 2 Combine

P = 8 + 3y

Note 3y must be less than 8. That's because 2 sides of any triangle must be larger than the 3rd side or else you don't have a triangle.

7 0

2 years ago

I need help asap <br> Pleasssee

Svetllana [295]

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2 years ago

Read 2 more answers

One watering system needs about three times as long to complete a job as another warning system when both systems operate at the

algol13

Answer:

One watering system requires 36 minutes to complete the job alone while another watering system requires 12 minutes to complete the job alone.

Step-by-step explanation:

Given:

Both the system can complete the job = 9 minutes

We need find the time required by each system to do the job.

Solution:

Let the time required by another watering system to complete the job be 'x' mins.

Now given:

One watering system needs about three times as long to complete a job as another watering system.

Time required by one watering system = $3x$

Rate to complete the job by another watering system = $\frac{1}{x}\ job/min$

Rate to complete the job by One watering system = $\frac{1}{3x}\ job/min$

Rate at which both can complete the job = $\frac{1}{9}\ job/min$

So we can say that;

Rate at which both can complete the job is equal to sum of Rate to complete the job by another watering system and Rate to complete the job by One watering system.

framing in equation form we get;

$\frac{1}{x}+\frac{1}{3x}=\frac19$

Now taking LCM to make the denominator common we get;

$\frac{1\times3}{x\times 3}+\frac{1\times1}{3x\times1}=\frac19\\\\\frac{3}{3x}+\frac{1}{3x}=\frac19\\\\\frac{3+1}{3x}=\frac{1}{9}\\\\\frac{4}{3x}=\frac{1}{9}$

By Cross multiplication we get;

$4\times9 =3x\\\\3x =36$

Dividing both side by 3 we get;

$\frac{3x}{3}=\frac{36}{3}\\\\x=12\ min$

Time required by One watering system = $3x =3\times 12 =36\ min$

Hence One watering system requires 36 minutes to complete the job alone while another watering system requires 12 minutes to complete the job alone.

6 0

2 years ago

You are taking hang-gliding lessons. The cost of the first lesson is one and a half times the cost of each additional lesson. Yo

kow [346]

So, givens: total lesson cost of $260, total lessons taken are 6, and the first lesson costs 1.5 (or 3/2) as much as the additional lessons.

First thing to do is to figure out how many additional lessons are in that, which are 5.

Then you can make a 1 variable equation with the information you have. I’m using x as my variable.

260= 3/2x + 5x

Combine like terms.

260 = 13/2x

Divide both sides by 13/2 (treat it as a fraction, and if your calculator cannot make fractions, then decimal might help for this. 13/2=6.5)

X=40

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1 year ago