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nataly862011 [7]
3 years ago
11

Identify the horizontal asymptote of f(x) =x2+5x-3/4x-1

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
5 0

since the numerator is x² + 5x - 3, and therefore has a degree of 2, whilst the denominator, 4x¹ - 1, has a degree of 1, therefore, there's no horizontal asymptote.

recall, we only get a horizontal asymptote if the denominator's expression degree is equals or greater than that of the numerator's.

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PLEASE HELP ASAP.
SashulF [63]

Answer:

x=13

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Step-by-step explanation:

ΔABC : isosceles    

vertex ∠A = 4x -6

∠B = ∠C = 5x + 2

∠A + ∠B + ∠C = 180° = (4x -6) + 2 * (5x + 2) = 14x - 2

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Jlenok [28]

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Answer:

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Step-by-step explanation:

Step one:

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-2x - 8y = -30-------1\\\\2x + 8y = 36--------2

Step two:

let us subtract the equations

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