The answer is the option A, which is: A. x-7=x²+2x-4
The explanation is shown below:
To solve this problem you must apply the proccedure shown below:
1. You have the following system equations given in the problem above:
<span>y=x-7
y=x²+2x-4
2. Therefore, when you substitute for y in the bottom equation, you obtain:
</span>x-7=x²+2x-4
1. C.
The rule of powers is that when a parenthesis is raised to a power, you multiply the two numbers. Since it is being raised to the second power, it needs to have a 10 in the parenthesis. That would make 20.
2. B
Firstly 10^2 = 100, so we know that the number must be 10. That leaves us with just A and B. Then we know the same thing from the previous equation, that they need to be multiplied together.
Answer:
Simplify the denominator.
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x
(
x
+
3
)
(
x
−
3
)
⋅
3
x
x
2
−
5
x
+
6
Factor
x
2
−
5
x
+
6
using the AC method.
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x
(
x
+
3
)
(
x
−
3
)
⋅
3
x
(
x
−
3
)
(
x
−
2
)
Finding the LCD of a list of values is the same as finding the LCM of the denominators of those values.
(
x
+
3
)
(
x
−
3
)
,
(
x
−
3
)
(
x
−
2
)
The LCM is the smallest positive number that all of the numbers divide into evenly.
1. List the prime factors of each number.
2. Multiply each factor the greatest number of times it occurs in either number.
The number
1
is not a prime number because it only has one positive factor, which is itself.
Not prime
The LCM of
1
,
1
is the result of multiplying all prime factors the greatest number of times they occur in either number.
1
The factor for
x
+
3
is
x
+
3
itself.
(
x
+
3
)
=
x
+
3
(
x
+
3
)
occurs
1
time.
The factor for
x
−
3
is
x
−
3
itself.
(
x
−
3
)
=
x
−
3
(
x
−
3
)
occurs
1
time.
The factor for
x
−
2
is
x
−
2
itself.
(
x
−
2
)
=
x
−
2
(
x
−
2
)
occurs
1
time.
The LCM of
x
+
3
,
x
−
3
,
x
−
3
,
x
−
2
is the result of multiplying all factors the greatest number of times they occur in either term.
(
x
+
3
)
(
x
−
3
)
(
x
−
2
)
Step-by-step explanation:
there does that help
Answer:False
Step-by-step explanation:#UwU God
Answer:
5
Step-by-step explanation:
You solve the equation
