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Korolek [52]
2 years ago
13

WILL MARK BRANLIESTTT What is the value of x? A. 42° B. 48 C. 64° D. 84

Mathematics
1 answer:
valkas [14]2 years ago
8 0

Answer:

<h2>D.84</h2>

Step-by-step explanation:

<u>*It's an isosceles triangle so 2 of the angles are going to be the same degrees</u>

<u>*Every triangle is 180 degrees</u>

(48)+(48)=96 then 180-96=84

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andrezito [222]

Answer:

7inches

Step-by-step explanation:

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2 years ago
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Can any one please help me I really need help please help me thank you
lina2011 [118]

Answer:

Jack has to sell the old computers worth $8000

Step-by-step explanation:

Jack is paid for selling used computers = $15 per hour plus 5% commission

Let the revenue generated from selling the computers by him = $x

He will be paid for 40 hours = $(40×15) = $600

Commission earned by selling x computers = $0.05x

Total amount earned by him in 40 hours week = 600 + 0.05x

If this amount is $1000,

$1000 = $(600 + 0.05x)

0.05x = 1000 - 600

0.05x = 400

x = \frac{400}{0.05}

x = $8000

Therefore, Jack has to sell the old computers worth $8000.

7 0
2 years ago
It seems to you that fewer than half of people who are registered voters in the City of Madison do in fact vote when there is an
Ad libitum [116K]

Answer:

a) Going to public places like restaurants, parks, theaters, etc in Madison and asking voters.

b) The 80% CI to estimate the true proportion of registered voters in the City of Madison who vote in non-presidential elections is (0.5533, 0.6667).

c) We are 80% sure that our confidence interval contains the true proportion of registered voters in the City of Madison who vote in non-presidential elections.

d) The lower limit of the interval is higher than 0.5. This means that it does seem that MORE than half of registered voters in the City of Madison vote in non-presidential elections.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence interval 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

Z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

(a) How might a simple random sample have been gathered?

Going to public places like restaurants, parks, theaters, etc in Madison and asking voters.

(b) Construct an 80% CI to estimate the true proportion of registered voters in the City of Madison who vote in non-presidential elections.

You take an SRS of 200 registered voters in the City of Madison, and discover that 122 of them voted in the last non-presidential election. This means that n = 200, \pi = \frac{122}{200} = 0.61.

We want to build an 80% CI, so \alpha = 0.20, z is the value of Z that has a pvalue of 1 - \frac{0.20}{2} = 0.90[tex], so [tex]z = 1.645.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{200}} = 0.61 - 1.645\sqrt{\frac{0.61*0.39}{200}} = 0.5533

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{200}} = 0.61 + 1.645\sqrt{\frac{0.61*0.39}{200}} = 0.6667

The 80% CI to estimate the true proportion of registered voters in the City of Madison who vote in non-presidential elections is (0.5533, 0.6667).

(c) Interpret the interval you created in part (b).

We are 80% sure that our confidence interval contains the true proportion of registered voters in the City of Madison who vote in non-presidential elections.

(d) Based on your CI, does it seem that fewer than half of registered voters in the City of Madison vote in non-presidential elections? Explain.

The lower limit of the interval is higher than 0.5. This means that it does seem that MORE than half of registered voters in the City of Madison vote in non-presidential elections.

4 0
3 years ago
3h-5h+11=17 Solve Equation.
chubhunter [2.5K]
The answer is -3
hope this help!!!!!
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3 years ago
g Programs submitted by programs in a computer science course are examined for syntax errors and logic errors. Suppose 36% of al
Llana [10]

Answer:

The answer is below

Step-by-step explanation:

Let S denote syntax errors and L denote logic errors.

Given that P(S) = 36% = 0.36, P(L) = 47% = 0.47, P(S ∪ L) = 56% = 0.56

a) The probability a program contains both error types = P(S ∩ L)

The probability that the programs contains only syntax error = P(S ∩ L') = P(S ∪ L)  - P(L) = 56% - 47% = 9%

The probability that the programs contains only logic error = P(S' ∩ L) = P(S ∪ L)  - P(S) = 56% - 36% = 20%

P(S ∩ L) = P(S ∪ L) - [P(S ∩ L') + P(S' ∩ L)] =56% - (9% + 20%) = 56% - 29% = 27%

b) Probability a program contains neither error type= P(S ∪ L)' = 1 - P(S ∪ L) = 1 - 0.56 = 0.44

c)  The probability a program has logic errors, but not syntax errors =   P(S' ∩ L) = P(S ∪ L)  - P(S) = 56% - 36% = 20%

d) The probability a program either has no syntax errors or has no logic errors = P(S ∪ L)' = 1 - P(S ∪ L) = 1 - 0.56 = 0.44

6 0
3 years ago
Read 2 more answers
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