Answer:
Step-by-step explanation:
c(t)=40:0≤t≤400
=40+0.50 (t-400):t≥400
It's 6x-18
Hope this helps
Answer:
a) 3.128
b) Yes, it is an outerlier
Step-by-step explanation:
The standardized z-score for a particular sample can be determined via the following expression:
z_i = {x_i -\bar x}/{s}
Where;
\bar x = sample means
s = sample standard deviation
Given data:
the mean shipment thickness (\bar x) = 0.2731 mm
With the standardized deviation (s) = 0.000959 mm
The standardized z-score for a certain shipment with a diameter x_i= 0.2761 mm can be determined via the following previous expression
z_i = {x_i -\bar x}/{s}
z_i = {0.2761-0.2731}/{ 0.000959}
z_i = 3.128
b)
From the standardized z-score
If [z_i < 2]; it typically implies that the data is unusual
If [z_i > 2]; it means that the data value is an outerlier
However, since our z_i > 3 (I.e it is 3.128), we conclude that it is an outerlier.
Let’s set this equation up to make this easier.
melanie= 2 1/5 miles walked
cathy= 1 3/4 more times than melanie.
when an equation says the word, more than this means adding. when it says less than this means subtraction. when it says times (in this question) then multiply.
so, if cathy walked 1 3/4 more times than melanie what we would do is multiply 1 3/4 to what melanie was walking. so 2 1/5 times 1 3/4 which equals 3.85.
so overall, cathy walked 3.85 more miles than melanie.
The answer is 0.00347222222
