Two rectangles have the same area of 70m2. It is given that the length of the first rectangle is 4m longer and the width is 2m s

Question

Ahat [919]

3 years ago

13

Two rectangles have the same area of 70m2. It is given that the length of the first rectangle is 4m longer and the width is 2m s

horter than the dimensions of the second rectangle. Find the lengths of the sides of these rectangles.

Mathematics

1 answer:

meriva · Answer 1 · 2022-08-21T03:35:07+03:00

The answer is the first rectangle has the length 14 m and the width 5 m. The second rectangle has the length 10 m and the width 7 m.

The equation is...
70=(70/y+4)*(y-2) {y= width of the first rectangle}
and when you solve you get y is either -5 or 7 and because -5 doesn't make sense y is equal to 7