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2 years ago

Which of the following is the correct factorization of the polynomial below? 2x^2-8x+8

Mathematics

2 answers:

Akimi4 [234]2 years ago

5 0

Answer:

2(x-2)²

Step-by-step explanation:

We have to factorize the given expression.

2x² - 8x + 8 = 2[x²- 4x + 4]

= 2(x - 2)² [since (a-b)² = a² + b² - 2ab]

Therefore, 2(x-2)² is the correct factorized form.

il63 [147K]2 years ago

4 0

The correct factorization is
2(x-2)²

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Step-by-step explanation:

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3 years ago

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goldfiish [28.3K]

Answer:

$0.69 for each bag

Step-by-step explanation:

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3 years ago

Solve: 2cos(x)-square root 3=0 for 0 less than x less than 2 pi

Leona [35]

Answer:

The general solution of $cos x = cos(\frac{\pi }{6})$ is

x = 2nπ± $\frac{\pi }{6}$

The general solution values

$x = - \frac{\pi }{6} and x = \frac{\pi }{6}$

Step-by-step explanation:

Explanation:-

Given equation is

$2cosx-\sqrt{3} =0 for 0$

$2cosx =\sqrt{3}$

Dividing '2' on both sides, we get

$cos x =\frac{\sqrt{3} }{2}$

$cos x = cos(\frac{\pi }{6})$

General solution of cos θ = cos ∝ is θ = 2nπ±∝

Now The general solution of $cos x = cos(\frac{\pi }{6})$ is

x = 2nπ± $\frac{\pi }{6}$

put n=0

$x = - \frac{\pi }{6} and x = \frac{\pi }{6}$

Put n=1

$x = 2\pi +\frac{\pi }{6} = \frac{13\pi }{6}$

$x = 2\pi -\frac{\pi }{6} = \frac{11\pi }{6}$

put n=2

$x = 4\pi +\frac{\pi }{6} = \frac{25\pi }{6}$

$x = 4\pi -\frac{\pi }{6} = \frac{23\pi }{6}$

And so on

But given 0 < x< 2π

The general solution values

$x = - \frac{\pi }{6} and x = \frac{\pi }{6}$

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3 years ago

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stiv31 [10]

Answer:

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Step-by-step explanation:

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