We want to find
, for
.
Recall the product rule: for 2 differentiable functions f and g, the derivative of their product is as follows:
.
Thus,
![y'=[(x^2+2)^3]'[(x^3+3)^2]+[(x^3+3)^2]'[(x^2+2)^3]\\\\ =3(x^2+2)^2(x^3+3)^2+2(x^3+3)(x^2+2)^3](https://tex.z-dn.net/?f=y%27%3D%5B%28x%5E2%2B2%29%5E3%5D%27%5B%28x%5E3%2B3%29%5E2%5D%2B%5B%28x%5E3%2B3%29%5E2%5D%27%5B%28x%5E2%2B2%29%5E3%5D%5C%5C%5C%5C%20%3D3%28x%5E2%2B2%29%5E2%28x%5E3%2B3%29%5E2%2B2%28x%5E3%2B3%29%28x%5E2%2B2%29%5E3)
Answer: A)
.
Vertex = (2, 2)
Range = {f(x): f(x) >= 2}
Step-by-step explanation:
15 - c = 6
15 - 6 = c
9 = c
c = 9
The scale factor is 2
x = 11.5
14/7 = 2
23/x = 2
x = 11.5
Answer: This parabola has 0.3875 x-intercepts,
<span>representing the times when the dolphin's height above water is </span>
0 feet.
The x-intercept is the point where the graph crosses the x-axis, which is when the value is y=0.
The calculation for y=0 would be
<span>Y = -16x2 + 32x - 10
</span><span>0 = -16x2 + 32x - 10
</span>-8x2 + 16x - 5=0
-b +-√(b^2-4ac) /2a=
-16 +-√(16^2-4(-8)(-5)) /2(-8) =
-16+- √(256-160/ -16 =
-16+- √(96/ -16 =
-16+- 9.8/ -16 =
x1= 0.3875
x2= -1.6125
