Question

The volume of a certain gas is 29.3 liters at STP. What would be the volume of the same gas at 1.39 atmospheres and -23.00C? (R=0.0821 L-atm/mol.k)
19.3L
22.4L
23.0L
37.31

Answer 1

Answer:

19.32L

Explanation:

Given parameters:

Volume of the gas at STP = 29.3liters;

      Using this information first, let us find the number of moles of the gas.

                  Number of moles = $\frac{volume of gas}{22.4}$

With the number of moles, we can further solve this problem;

                 Number of moles  = $\frac{29.3}{22.4}$   = 1.31 moles

More parameters;

Pressure on gas  = 1.39atm

temperature  = -23°C  = -23 + 273  = 250K

Unknown:

Volume of gas  = ?

Solution:

The ideal gas equation is the perfect fix to solve this problem.

It is mathematically expressed as;

              Pv  = nRT

where P is the pressure

           v is the volume

           R is the gas constant

            n is the number of moles

            T is the temperature

     Input the parameters;

             1.39 x V  = 1.31 x 0.082 x 250

                     V  = 19.32L