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Gnom [1K]
3 years ago
5

Solve for

Mathematics
2 answers:
il63 [147K]3 years ago
3 0
Hello there!

y² + 6y + 5 = 0
Let's factor this equation.

(y+1)(y+5) = 0

y + 1 = 0                 y + 5 = 0
      y = -1                      y = -5

So your answers are...
y = -1 , y = -5
FinnZ [79.3K]3 years ago
3 0
-------------------------------------------------
Equation
-------------------------------------------------
y² + 6y + 5 = 0

-------------------------------------------------
Factorize it
-------------------------------------------------
(x + 5)(x + 1) = 0

-------------------------------------------------
Apply the zero product property rule
-------------------------------------------------
x + 5 = 0 or x + 1 = 0

x = -5 or x = -1

-------------------------------------------------
Answer: -5, -1
-------------------------------------------------
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3 years ago
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Juanita keeps 25% of the profit from her ice cream shop. If the shop makes $750 per month, how much money will Juanita keep?
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Find the product of all real values of r for which 1/2x=r-x/7
Dahasolnce [82]

Answer:

r = \±\sqrt{14

Product = -14

Step-by-step explanation:

Given

\frac{1}{2x} = \frac{r - x}{7}

Required

Find all product of real values that satisfy the equation

\frac{1}{2x} = \frac{r - x}{7}

Cross multiply:

2x(r - x) = 7 * 1

2xr - 2x^2 = 7

Subtract 7 from both sides

2xr - 2x^2 -7= 7 -7

2xr - 2x^2 -7= 0

Reorder

- 2x^2+ 2xr  -7= 0

Multiply through by -1

2x^2 - 2xr +7= 0

The above represents a quadratic equation and as such could take either of the following conditions.

(1) No real roots:

This possibility does not apply in this case as such, would not be considered.

(2) One real root

This is true if

b^2 - 4ac = 0

For a quadratic equation

ax^2 + bx + c = 0

By comparison with 2x^2 - 2xr +7= 0

a = 2

b = -2r

c =7

Substitute these values in b^2 - 4ac = 0

(-2r)^2 - 4 * 2 * 7 = 0

4r^2 - 56 = 0

Add 56 to both sides

4r^2 - 56 + 56= 0 + 56

4r^2 = 56

Divide through by 4

r^2 = 14

Take square roots

\sqrt{r^2} = \±\sqrt{14

r = \±\sqrt{14

Hence, the possible values of r are:

\sqrt{14 or -\sqrt{14

and the product is:

Product = \sqrt{14} * -\sqrt{14}

Product = -14

8 0
3 years ago
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salantis [7]
..........................................
5 0
3 years ago
-0.111c + 1 = 0.889c
Elena-2011 [213]

Answer:

-0.111c + 1 = 0.889c = c=1

Subtract 0.889c from both sides:

−0.111c+1−0.889c=0.889c−0.889c

−c+1=0

Subtract 1 from both sides.:

−c+1−1=0−1

−c=−1

Divide both sides by -1.:

-c/1 = -1/-1

Therefore, your answer is c=1

7 0
3 years ago
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