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KengaRu [80]
3 years ago
13

I need an answer for number 5

Mathematics
1 answer:
notka56 [123]3 years ago
7 0

Answer:

Step-by-step explanation:

Go

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Molly was allowed to trick or treat from 6:30 pm to 8:45pm if she averaged coating 2 houses every 9 minutes during that time how
MissTica

Answer:

30 houses

Step-by-step explanation:

Time from 6:30 pm to 8:45 pm = 2 hr 15 min

Time in minutes = (2 hr × 60 min/hr) + 15 min = 135 min

Average visit = 9 min per 2 houses = 4.5 min per house

Number of visits = 135 min ÷ 4.5 min/house = 30 houses

3 0
2 years ago
Answer is 345 make an equation from 100, 10, 3, 4, 5, 2, 1
Tpy6a [65]

Answer: 10 × 3 + 4 + 5 × 2 + 1 + 3 × 100 = 345

8 0
2 years ago
Select ALL the correct answers.
Marina CMI [18]

Answer:

The median of A is the same as the median of B.

The interquartile range of B is greater than the interquartile range of A.

Step-by-step explanation:

Given that:

A = number of runs allowed in first 9 games

A = {1, 4, 2, 2, 3, 1, 1, 2, 1}

Rearranging A : 1, 1, 1, 1, 2, 2, 2, 3, 4

Median A = 1/2(n + 1) th term

Median A = 1/2(10) = 5th term = 2

Q1 of A = 1/4(10) = 2.5th term = (1 + 1)/ 2 = 1

Q3 of A = 3/4(10) = 7.5th term = (2+3)/2 = 2.5

Interquartile range = Q3 - Q1 = 2.5 - 1 = 1.5

Number of runs allowed in 10th game = 9

B = {1, 4, 2, 2, 3, 1, 1, 2, 1, 9}

Rearranging B = 1, 1, 1, 1, 2, 2, 2, 3, 4, 9

Median A = 1/2(n + 1) th term

Median A = 1/2(11) = 5.5th term = (2+2)/2 = 2

Q1 of A = 1/4(11) = 2.75th tetm = (1 + 1)/ 2 = 1

Q3 of A = 3/4(11) = 8.25th term = (3+4)/2 = 3.5

Interquartile range = Q3 - Q1 = 3.5 - 1 = 2.5

Median A = 2 ; median B = 2

IQR B = 2.5 ; IQR A = 1.5 ; IQR B > IQR A

7 0
2 years ago
Factor completely 5x2 − 40.
Tatiana [17]

,Answer:

I got -30

Step-by-step explanation:

Becuase when I did 5 x 2= 10

and 10 -40 = -30

3 0
3 years ago
PLEASE HELP
Reil [10]
Is there a graph or anything given
6 0
2 years ago
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