9•44=396
396/54=7.3 repeating
Therefore y=7.33
Answer:
-4/9
Step-by-step explanation:
We first calculate the first bracket.
[2/3-(-4/9)]
= (2/3+4/9) (we cancel out the negatives)
= (6/9+4/9) (common denominator)
= 10/9
Then we convert -2 1/2 into an improper fraction.
-2 1/2
= -5/2
Finally we calculate the division by swapping the numerator and denominator of -5/2.
10/9 / -5/2
= 10/9 * -2/5
= -20/45
= -4/9 (simplify the terms)
Answer:
a) 81
b) 16,807
c) 100
d) 78125
Step-by-step explanation:
a)
3^2 x 3^2
Step 1. Simplify the exponents
3^2 = 3 x 3 = 9
Step 2. Multiply
9 x 9 = 81
••••••••••••••••••••••••••••••••
b)
7 x 7^4
Step 1. Simplify the exponent
7^4 = 7 x 7 x 7 x 7 = 2401
Step 2. Multiply
7 x 2401 = 16,807
••••••••••••••••••••••••••••••••
c)
10^9 divided by 10^7
Step 1. Simplify the exponents
10^9 = 10 x 10 x 10 x 10 x 10 x 10 x 10 x 10 x 10 = 1000000000
10^7 = 10 x 10 x 10 x 10 x 10 x 10 x 10 = 10000000
Step 2. Divide
1000000000 divided by 10000000 = 100
••••••••••••••••••••••••••••••••
d)
5^8 divided by 5
Step 1. Simplify the exponent
5^8 = 5 x 5 x 5 x 5 x 5 x 5 x 5 x 5 = 390625
Step 2. Divide
390625 divided by 5 = 78125
Answer:
The probability of friend A winning with HH = 1/4.
Step-by-step explanation:
The probability of an event, A is P(A) given by the relationship;
P(A) = (The number of required outcome)/(The number of possible outcomes)
The parameters given are;
The condition of friend A winning = Coin toss sequence HH shows up
The condition of friend B winning = Coin toss sequence TH shows up
The number of possible outcomes = TT, TH, HH, HT = 4
(TH and HT are taken as different for the game to be fair)
The number of required outcome = HH = 1
Therefore;
The probability of friend A winning with HH = 1/4.
