If
, then by definition of absolute value
![|1-4x| = 1-4x > 7 \implies 4x < -6 \implies x < -\dfrac32](https://tex.z-dn.net/?f=%7C1-4x%7C%20%3D%201-4x%20%3E%207%20%5Cimplies%204x%20%3C%20-6%20%5Cimplies%20x%20%3C%20-%5Cdfrac32)
On the other hand, if
, then
![|1-4x| = -(1-4x) = -1 + 4x > 7 \implies 4x > 8 \implies x > 2](https://tex.z-dn.net/?f=%7C1-4x%7C%20%3D%20-%281-4x%29%20%3D%20-1%20%2B%204x%20%3E%207%20%5Cimplies%204x%20%3E%208%20%5Cimplies%20x%20%3E%202)
So, the overall solution to the inequality is interval union
![\left(x < -\dfrac32\right) \cup (x > 2)](https://tex.z-dn.net/?f=%5Cleft%28x%20%3C%20-%5Cdfrac32%5Cright%29%20%5Ccup%20%28x%20%3E%202%29)
Answer:
x=-3/2 or x=0
Step-by-step explanation:
Subtract 8 from both sides
3|4x+3|+8-8=17-8
Simplify
3|4x+3| = 9
Divide both sides by 3
3|4x+3|/3 = 9/3
Simplify
|4x+3|=3
Apply absolute rule
4x+3=-3 or 4x+3=3
Solve
x=-3/2 or x=0
Okay. So 3 guests are free. Mika has $42 dollars she can spend with $7 per guest. 42/7 = 6. Add the 3 other guests and you get 9. Mika can bring 3 guests with her to the gym. D gives the correct answer, and A and B give out the correct equations as well. C is not right, because 7 * 9 is 63. 63 - 3 is 60. 60 > 42. C is the incorrect equation. The answer is C.
Hello,
606 is divisble by 2 since 6 is divisible by 2 (last digit).
606 is divisible by 3 since 6+0+6=12 which is divisible by 3
606 is not divisible by 4 since 04 is not divisible by 4 (last 2 digits)
606 is divisible by 6 since 606 is divisible by 2 and by 3 thus by 6.