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Mumz [18]
3 years ago
8

The average radius of Jupiter is 4.34 x 10^4 miles. The average sun radius of the sun is 4.32 x 10^5. How many times greater is

the average radius of the sun?
Mathematics
1 answer:
Oksanka [162]3 years ago
7 0

Answer:

The average radius of sun is approximately 9.95 times the average radius of Jupiter.                                

Step-by-step explanation:

We are given the following in the question:

Average radius of Jupiter =

4.34\times 10^{4}\text{ miles}

Average radius of the sun =

4.32\times 10^{5}

Relation between average radius of sun and average radius of Jupiter =

\displaystyle\frac{\text{Average radius of Sun}}{\text{Average radius of Jupiter}}\\\\= \frac{4.32\times 10^{5}}{4.34\times 10^{4}}\\\\\displaystyle\frac{\text{Average radius of Sun}}{\text{Average radius of Jupiter}} = 9.953917\\\\\text{Average radius of Sun} \approx 9.95\times \text{(Average radius of Jupiter)}

Thus, the average radius of sun is approximately 9.95 times the average radius of Jupiter.

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mojhsa [17]

Answer:

2998 ; 17%

Step-by-step explanation:

Given the function:

t(c)=-3970.9(ln c)

c = % of carbon remaining ; t = time

1.) c = 47% = 47/100 = 0.47

t(0.47) = - 3970.9(In 0.47)

t = - 3970.9 * −0.755022

t = 2998.119

t = 2998

B.)

t = 7000

t(c)=-3970.9(ln c)

7000 = - 3970.9(In c)

7000 / - 3970.9 = In c

−1.762824 = In c

c = exp(−1.762824)

c = 0.1715596

c = 0.1715596 * 100%

c = 17.156% ; c = 17%

8 0
3 years ago
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Ksivusya [100]
\bf \qquad \qquad \textit{quadratic formula}\\\\

\begin{array}{lcclll}
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a&b&c
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\qquad \qquad 
x= \cfrac{ - {{ b}} \pm \sqrt { {{ b}}^2 -4{{ a}}{{ c}}}}{2{{ a}}}
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1. (2 points) Solve each equation and write the answer on the line
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Eighteen tens < 21 × (5+5)

Hope this helps!
7 0
4 years ago
Need help please thanks
tangare [24]

Answer:

i think it would be b

Step-by-step explanation:

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The fuel capacity of a popular hybrid car is 11.9 gallons. The function for this situation is f(x) = -0.02x + 11.9, where x repr
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Answer:

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Step-by-step explanation:

You're in luck. The fuel consumption of the car is linear, and the slope - ie, the coefficent of the x term gives you the rate of change. In this case, it's -0.02 gallons per mile.

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