The answer I think it would be -6 right?
Answer:
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Step-by-step explanation:
<u>Question:</u>
Find the number of real number solutions for the equation. x^2 + 5x + 7 = 0
<u>Answer:</u>
The number of real solutions for the equation is zero
<u>Solution:</u>
For a Quadratic Equation of form : ---- eqn 1
The solution is
Now , the given Quadratic Equation is ---- eqn 2
On comparing Equation (1) and Equation(2), we get
a = 1 , b = 5 and c = 7
In , is called the discriminant of the quadratic equation
Its value determines the nature of roots
Now, here are the rules with discriminants:
1) D > 0; there are 2 real solutions in the equation
2) D = 0; there is 1 real solution in the equation
3) D < 0; there are no real solutions in the equation
Now let solve for given equation
Since -3 is less than 0, this means that there are 0 real solutions in this equation.
Answer:
x = 11, y = 3
Step-by-step explanation:
(13x - 19) and (9x + 25) are corresponding angles and congruent, thus
13x - 19 = 9x + 25 ( subtract 9x from both sides )
4x - 19 = 25 ( add 19 to both sides )
4x = 44 ( divide both sides by 4 )
x = 11
Then
13x - 19 = 13(11) - 19 = 143 - 19 = 124
(17y + 5) and 124 are alternate angles and are supplementary, thus
17y + 5 + 124 = 180, that is
17y + 129 = 180 ( subtract 129 from both sides )
17y = 51 ( divide both sides by 17 )
y = 3
Answer:
x= -3-sqr30/7
Step-by-step explanation: