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kakasveta [241]
3 years ago
5

PLS ANSWER QUICK! Thanks!

Mathematics
1 answer:
ziro4ka [17]3 years ago
5 0

Answer:

The correct answer would be a=\sqrt{c^2-b^2}

Step-by-step explanation:

given a^2+b^2=c^2 we want to solve for a

How?

We can do this by using basic algebra ( isolating the variable (a ))

Step 1 subtract b^2 from each side

a^2+b^2-b^2=a^2\\c^2-b^2=c^2-b^2

now we have a^2=c^2-b^2

step 2 take the square root of each side

\sqrt{a^2} =a\\\sqrt{c^2-b^2} =\sqrt{c^2-b^2}

we're left with a=\sqrt{c^2-b^2}

Hence your answer is A

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The measure of an angle is 51 degrees
ki77a [65]
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180 - 51 = x

x = 129

C) 129 degrees is your answer

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3 years ago
​Quadrilateral ABCD​ is inscribed in this circle. What is the measure of ∠A?
mamaluj [8]

Answer:

Step-by-step explanation:

7 0
3 years ago
A^2(64a^2-3)/3=27-4a^2/4
frutty [35]
The answer is a = 3/4 = 0.75

First get rid of the paranthesis,
{a}^{2} (64 {a}^{2}  - 3) = 64 {a}^{4} -  3 {a}^{2}
Then set the denominators equal:
\frac{ 256 {a}^{4}  - 12 {a}^{2}}{12}  =  \frac{81 - 12 {a}^{2} }{12}
Then remove the denominators and solve:
256 {a}^{4}  - 12 {a}^{2}  = 81 - 12 {a}^{2}
Eliminate -12a^2 by adding 12a^2 to both sides:
256 {a}^{4}  = 81
Take the fourth root of them or take the square root twice:
\sqrt[4]{256 {a}^{4} }  =  \sqrt[4]{81}   \\  4a = 3
Divide both sides by 4:
a =  \frac{3}{4}  = 0.75
7 0
3 years ago
Where is the point (-1,5) located on the coordinate plane?
weqwewe [10]
The point (-1, 5) is located here:

Yes, I did draw that in paint just for you.

3 0
4 years ago
Read 2 more answers
Can someone pls help im new to this
Serggg [28]

Answer:

5

Step-by-step explanation:

\frac{-10}{-2} \\\\5

3 0
3 years ago
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