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4 years ago

Enter the distance between points (4, -7) and (-5,5) on the coordinate plane. units

Mathematics

1 answer:

Aloiza [94]4 years ago

3 0

Answer:

piontttttsssssssss

Step-by-step explanation:

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penology

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4 years ago

1/4 of 1% expressed as a decimal

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3 years ago

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4.2r - 12.68 = 10<br> how to sole it to plz

Y_Kistochka [10]

R=5.4

4.2r-12.68=10
+12.68 +12.68
4.2r=22.68
4.2/4.2 22.68/4.2
22.68/4.2= 5.4

Hope this helps! Have a great day :)

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3 years ago

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Find f^-1(x) for the function f(x)=x/3 F^-1(x)= ?x

Liula [17]

Answer:

f^-1(x)=3x

Step-by-step explanation:

y=x/3

to get the inverse function, exchange x and y,

x=y/3

solve for y, y=3x

f^-1(x)=3x

4 0

3 years ago

Question 20 not yet answered marked out of 1.00 not flaggedflag question question text luna created a trash can in the shape of

Alex Ar [27]

Consider the triangle with sides a=1.6, b=2.3 and c=1.2 feet. You can use cosine theorem twice to find two unknown angles:

$b^2=a^2+c^2-2ac\cos \angle B,\\ (2.3)^2=(1.6)^2+(1.2)^2-2\cdot 1.6\cdot 1.2\cos \angle B,\\ 5.29=2.56+1.44-3.84\cos \angle B,\\ 3.84\cos \angle B=4-5.29=-1.29,\\\cos \angle B=-\dfrac{1.29}{3.84} =-0.336$

Then you can conclude that ∠B is obtuse (because $\cos \angle B$ ) and m∠B=110°.

$c^2=a^2+b^2-2ab\cos \angle C,\\ (1.2)^2=(1.6)^2+(2.3)^2-2\cdot 1.6\cdot 2.3\cos \angle C,\\ 1.44=2.56+5.29-7.36\cos \angle C,\\ 7.36\cos \angle C=7.85-1.44=6.41,\\\cos \angle C=\dfrac{6.41}{7.36} =0.871$ .

Then you can conclude that ∠C is acute (because $\cos \angle C>0$ ) and m∠C=29°.

3. m∠A+m∠B+m∠C=180°, then m∠A=180°-110°-29°=41°.

Answer: m∠A=41° (∠A is opposite to the side a=1.6), m∠B=110° (∠B is opposite to the side b=2.3) and m∠C=29° (∠C is opposite to the side c=1.2)

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3 years ago