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Eduardwww [97]
3 years ago
6

in an arithmetic progression the thirteenth term is 27 and the seventh term is three times the second term,find the first term,t

he common difference and the sum of the first terms​
Mathematics
1 answer:
GuDViN [60]3 years ago
8 0

Answer:

penology

Step-by-step explanation:

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Simplify the difference quotient f ( x + h ) â f ( x ) h for the function f ( x ) = 6 x â x 2
ladessa [460]

Answer:

final answer is 6

Step-by-step explanation:

Given f(x)=6x-2

To find the difference quotient use formula

\frac{f(x+h)-f(x)}{h}

f(x)=6x-2

f(x+h)=6(x+h)-2=6x+6h-2

Now plug it in the formula

\frac{f(x+h)-f(x)}{h}

\frac{6x+6h-2-(6x-2)}{h}

\frac{6x+6h-2-6x+2)}{h}

\frac{6h}{h}

6

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4 years ago
Read 2 more answers
The sum of three integers is 92. The second number is three times the first number. The third number is ten less than twice the
SVEN [57.7K]
Given,
The sum of three integers is 92

So,
Let,
The first integer be "x"
The second integer be "y"
The third integer be "z"

Now,
According to the question,
y = 3x          ..............equation (1)
z = 2x - 10    .............. equation (2)
x + y + z = 92 ..............equation (3)

Now,
Substituting the value of "y" and "z" from equation (1) and (2), we get,

x + (3x) + (2x - 10) = 92
    x + 3x + 2x - 10 = 92
                  6x - 10 = 92
                         6x = 92 + 10
                           x = 102 / 6
                           x = 17

Now,
substituting the value of "x" in equation (1)
 y = 3 (17)
y = 51

Now,
Substituting the value of "x" in equation (2),

z = 2 (17 ) - 10
z = 34 - 10
z = 24


So, the numbers are 17, 51 and 24


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