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Aneli [31]
4 years ago
12

What is the unit rate for:

Mathematics
1 answer:
Ierofanga [76]4 years ago
3 0

It would be .9 eggs per day. Divide 6 by 7 and get a high decimal. Then, round and bam. you got it.  6 ÷ 7 = 0.85714285714 rounded to .9

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Two more than4 times a number is -18
jonny [76]
-5, work backwards. you know 2 + 4 * ? = -18.
start by subtracting 2 from both sides giving you 4 * ? = -20.
now you divide 4 from both sides giving you ? = -5

i used ? to represent the missing number btw!!
6 0
3 years ago
Draw and label all three side lengths and angle measures of a right triangle that has a 40° angle and a hypotenuse 10 cm long.
Elodia [21]

Answer:

Right Triangles and the Pythagorean Theorem

1.The Pythagorean Theorem, a2+b2=c2, a 2 + b 2 = c 2 , can be used to find the length of any side of a right triangle.

2.The side opposite the right angle is called the hypotenuse (side c in the figure).

4 0
3 years ago
Which two triangles are reflections of each other across the x-axis?
Inessa05 [86]

Answer: Triangle A and Triangle C

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7 0
3 years ago
Read 2 more answers
The population of a certain inner-city area is estimated to be declining according to the model P(t)=184,000e^−0.012t, where t i
Alex73 [517]

Answer:

EZ answer 9+10=21

Step-by-step explanation:

4 0
3 years ago
Compute the determinant using a cofactor expansion across the first row. Also compute the determinant by a cofactor expansion do
V125BC [204]

Answer:

Step-by-step explanation:

It is given that

\Delta=\begin{vmatrix}3&0&3\\2 &3&3\\0 &4&-2\end{vmatrix}

By cofactor expansion across the first row, we get

\Delta=a_{11}C_{11}+a_{12}C_{12}+a_{13}C_{13}

\Delta=3\left[(-1)^{1+1}\begin{vmatrix}3&3\\4&-2\end{vmatrix}\right]+0\left[(-1)^{1+2}\begin{vmatrix}2&3\\0&-2\end{vmatrix}\right]+3\left[(-1)^{1+3}\begin{vmatrix}2&3\\0&4\end{vmatrix}\right]

\Delta=3\left[-18\right]+0\left[(-1)(-4)\right]+3\left[8\right]

\Delta=-54+0+24

\Delta=-30

Therefore, the value of determinant is -30.

By cofactor expansion across the second column, we get

\Delta=a_{12}C_{12}+a_{22}C_{22}+a_{32}C_{32}

\Delta=0\left[(-1)^{2+1}\begin{vmatrix}2&3\\0&-2\end{vmatrix}\right]+3\left[(-1)^{2+2}\begin{vmatrix}3&3\\0&-2\end{vmatrix}\right]+4\left[(-1)^{3+2}\begin{vmatrix}3&3\\2&3\end{vmatrix}\right]

\Delta=0\left[(-1)(-4)\right]+3\left[(-6)\right]+4\left[(-1)3\right]

\Delta=-18-12

\Delta=-30

Therefore, the value of determinant is -30.

7 0
4 years ago
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