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makvit [3.9K]
3 years ago
14

A salesman sold twice as much pears in the afternoon than in the morning. If he sold 360 kilograms of pears that day, how many k

ilograms did he sell in the morning and how many in the afternoon?
Mathematics
1 answer:
Lunna [17]3 years ago
4 0

Answer:Let x be the number of kilograms he sold in the morning.Then in the afternoon he sold 2x kilograms, so the total is x+2x=3x This must be equal to 360.Therefore, the salesman sold 120 kg in the morning and 240 kg in the afternoon.

Hope this helps :)

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Graham paid $87.45 for a pair of jeans. This amount included a tax of 40%. What was the cost of the jeans before tax?
kiruha [24]

The final price is the cost plus the tax.

Since we know the tax and a percent, we can write this as

T = C(1+r)

T = what Graham paid = $87.45

C = cost before tax

r = tax rate expressed as a decimal = .40

Plugging in what we know

87.45 = C (1+.4)

87.45 = C(1.4)

Divide both sides by 1.4

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Solve the system.
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X = y + 11

2x + y = -2
2(y + 11) + y = -2
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3y + 22 = -2
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x = -8 + 11
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What is the domain and range of the relation shown in the table?
TEA [102]

Answer:

<u>domain: {10,15,19,32}</u>

<u>range:{5,9,-1}</u>

Step-by-step explanation:

  • As we know domain is the values of input and range is the values of output.
  • Here , x is the input and y is the output.
  • \left[\begin{array}{cc}x&y\\10&5\\15&9\\19&-1\\32&5\end{array}\right]
  • Thus the input values according to the given problem is : 10 ,15 , 19, and thus ,

⇒<em>The domain would accordingly be these four numbers : 10 , 15 , 19 , 32.</em>

  • <u>Note that we donot have any information regarding the other values of x.</u>
  • The range is : { 5,9,-1 } only as the 5 is repeated in two cases .
  • Range is unique and there must be not repetition. Thus the apt answer would be :

<em>domain: {10,15,19,32}</em>

<em>range:{5,9,-1}</em>

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Answer:

b

Step-by-step explanation:

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3 years ago
Which is the equation of the line?
IRINA_888 [86]
Answer: (C)2x + 8Y = 16 

\underline{X || 2x + 8Y = 16 || Y}
\underline{0\:||\:2*0 + 8Y = 16\to\:8Y = 16\to\:Y =  \frac{16}{8}\:||\:Y = 2} (0,2)
\underline{8\:||\:2*8 + 8Y = 16\to\:8Y = 16-16\to\:Y = \frac{0}{8}\:||\:Y = 0} (8,0)

<span>Check the chart for a better understanding:
</span>



3 0
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