NEED THE HELP PLEAASE !!!

2 answers:

8 0

The perimeter of triangle XYZ will be:

40r + 30r + 60r = 130r

The area of triangle ABC is n² so the area of triangle XYZ will be n²×r²

LuckyWell [14K]3 years ago

6 0

Answer:

Part A. Option B.

Part B. Option C.

Step-by-step explanation:

The sides of ΔABC are 30 units, 40 units and 60 units long.

The corresponding sides of ΔXYZ are r times as long as the sides of ΔABC.

Therefore sides of ΔXYZ will be 30r units, 40r units and 60r units.

Perimeter of ΔXYZ = 30r + 40r + 60r = 130r

Option B. is the answer.

If the area of ΔABC is n square units then we have to find the area of ΔXYZ.

Since all sides of ΔXYZ are r times of ΔABC, so area of ΔABC = $\frac{1}{2}(Base)(height)$

Area of ΔXYZ = $\frac{1}{2}(r.height)(r.base)=n(r.r)$

= n(r)²

Option C is the answer.

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