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klio [65]
2 years ago
12

If k is a nonzero constant, what is the slope of the line containing the points (k,2k) and (3k,k)

Mathematics
1 answer:
ivolga24 [154]2 years ago
3 0

Answer:

The slope is -1/2

Step-by-step explanation:

m=\frac{y_2-y_1}{x_2-x_1}\\ \\m=\frac{k-2k}{3k-k}\\ \\m=\frac{-k}{2k}\\ \\m=-\frac{1}{2}

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Answer:

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\left[\begin{array}{ccc}x\\y\\z\end{array}\right]=\left[\begin{array}{c}a+2b\\b\\-3a\end{array}\right]=a\left[\begin{array}{c}1\\0\\-3\end{array}\right]+b\left[\begin{array}{c}2\\1\\0\end{array}\right]

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Also we can see that those vectors are linear independent. Then the set

\{\left[\begin{array}{c}1\\0\\-3\end{array}\right], \left[\begin{array}{c}2\\1\\0\end{array}\right]\} is a basis for W and the dimension of W is 2.

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ans is 127007..........

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