Slope: 2
y intercept: 5
rate of change : 2/1
Answer:
x = 40
Step-by-step explanation:
∠D = ∠ADB + ∠BDC
= 30 + 40
= 70°
In ΔBDC,
BD = CD
∠DBC = ∠DCB {angles opposite to equal sides are equal}
∠DBC + ∠DCB + ∠BDC = 180 {Angle sum property}
2∠DCB + 40 = 180
2∠DCB = 180 -40
2∠DCB = 140
∠DCB= 140/2
∠DCB = 70°
In ΔADC,
x + ∠D + ∠C = 180
x + 70 + 70 = 180
x + 140 = 180
x = 180 - 140
x = 40°
This is known as quadratic algebra.
To find it, you can use the quadratic formula but that might take a while.
We can factor it out and get
-3(mx² + mx - 1)
We can then set mx² + mx = 1
It would have no solutions
Edit: Above is wrong! I made the mistake of factoring 3 when it cant be factored.
Here is the solution
mx²-3mx=-3
Divide both by -3
mx²+mx=1
And I really messed this up. Its been a long time since quad. Sorry, but I cant seem to get the answer. Try and look up the quadratic formula and see if you can use that
<span>Simplifying
4x2 + -24x + 4y2 + 72y = 76
Reorder the terms:
-24x + 4x2 + 72y + 4y2 = 76
Solving
-24x + 4x2 + 72y + 4y2 = 76
Solving for variable 'x'.
Reorder the terms:
-76 + -24x + 4x2 + 72y + 4y2 = 76 + -76
Combine like terms: 76 + -76 = 0
-76 + -24x + 4x2 + 72y + 4y2 = 0
Factor out the Greatest Common Factor (GCF), '4'.
4(-19 + -6x + x2 + 18y + y2) = 0
Ignore the factor 4.
</span><span>Subproblem 1
Set the factor '(-19 + -6x + x2 + 18y + y2)' equal to zero and attempt to solve:
Simplifying
-19 + -6x + x2 + 18y + y2 = 0
Solving
-19 + -6x + x2 + 18y + y2 = 0
The solution to this equation could not be determined.
This subproblem is being ignored because a solution could not be determined.
The solution to this equation could not be determined.</span>