Ask question

Ask question

All categories

3 years ago

14

A person invest 7900 in an account growing at a rate allowing the money to double every 8 years. How much money would be in the

account after 5 years, to the nearest dollar

1 answer:

Aleonysh [2.5K]3 years ago

4 0

Answer:

There will be $7,900.

Step-by-step explanation:

Seeing as it will double every EIGHT years, and 5 is less than eight, the amount will stay the same.

You might be interested in

3) A number between 0 and 1, expressed as one number over another, is called a _ _ _ _ _ _ _ _.

Bond [772]

If you write a number over another number, it's called a FRACTION

5 0

3 years ago

Read 2 more answers

Which expression has the same value as 4x – 3y?

coldgirl [10]

Answer:

4x+(-3y)

Step-by-step explanation:

$\\ \rm\longmapsto 4x+(-3y)$

(-)(-)=(+)
(+)(-)=(-)
(-)(+)=(-)
(+)(+)=(+)

$\\ \rm\longmapsto 4x-3y$

5 0

2 years ago

The sum of two polynomials is –yz2 – 3z2 – 4y + 4. If one of the polynomials is y – 4yz2 – 3, what is the other polynomial? –2yz

marishachu [46]

The first polynomial is $y -4yz^2-3$ and let the second polynomial be P(y,z).

If the sum of two polynomials is $-yz^2-3z^2-4y+4$ , then $y-4yz^2-3+P(y,z)=-yz^2-3z^2-4y+4$ .

Take the first polynomial from the left side to the right side:

$P(y,z)=-yz^2-3z^2-4y+4 -(y-4yz^2-3),\\ P(y,z)=-yz^2-3z^2-4y+4 -y+4yz^2+3,\\ P(y,z)=3yz^2-3z^2-5y+7$ .

Answer: the second polynomial is $3yz^2-3z^2-5y+7$ .

3 0

3 years ago

Read 2 more answers

What is the algebraic expressions of 8-6k

Komok [63]

Eight decreased by six times the number k

The difference of eight and the product of six and the number k

Eight minus six times k

Six multiplied to k is less than 8

4 0

2 years ago

Use a proportion to estimate each population. (Please solve both questions, thank you) (I’ll reward you with brainliest :)

hammer [34]

Answer:

<em>Step-by-step explanation:</em>

<em>Step 1. (The capture) Capture a sample total counted =958, and them back tagged counted=38,total tagged=56 </em>

<em>The idea is to estimate the proportion p = m/N of tagged =102. </em>

<em>Step 2. (The recapture) After everything has settled down, capture a new sample of n fish. Count the number of tagged fish. Suppose that k of them are tagged. </em>

<em>It is reasonable that, k/n would be a good estimante for p = m/N. </em>

<em>Accordingly, for an estimate N of N, se solve the equation m/N= k/n. </em>

7 0

3 years ago