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otez555 [7]
4 years ago
12

A rectangle has an area of 144 in2 and a perimeter of 60 in. Find the length and width

Mathematics
1 answer:
kiruha [24]4 years ago
4 0

Answer:

The length is 24, width is 6

Step-by-step explanation:

Since we know the length and width cannot both be 12 (to make 144), other factors of 12 can be tested to be a product of 144. Half of 12 is 6, and 24 * 6 = 144. If we add up 12 + 12 + 6 + 6, we get 60, or the given perimeter.

Hope I helped and please give me brainliest!

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Radon is a gas produced when radium decays, and it can enter homes where it can be a health threat. Among 180 homes in Hyde Park
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Answer:

We are given that Among 180 homes in Hyde Park, 25 were found to have unsafe radon levels. Among 230 homes in La Grange, 50 were found to have unsafe radon levels.

Claim : the two towns have different rates of unsafe radon levels.

Let p_1 and p_2be the rates of unsafe radon levels of Hyde Park and LaGrange respectively .

H_0:p_1=p_2\\H_a:p_1\neq p_2

Among 180 homes in Hyde Park, 25 were found to have unsafe radon levels

So, n_1=180, y_1=25

Among 230 homes in La Grange, 50 were found to have unsafe radon levels.

So, n_2=230, y_2=50

We will use Comparing Two Proportions

\widehat{p_1}=\frac{y_1}{n_1}

\widehat{p_1}=\frac{25}{180}

\widehat{p_1}=0.1388

\widehat{p_2}=\frac{y_2}{n_2}

\widehat{p_2}=\frac{50}{230}

\widehat{p_2}=0.217

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Formula of test statistic :\frac{\widehat{p_1}-\widehat{p_2}}{\sqrt{\widehat{p}(1-\widehat{p})(\frac{1}{n_1}+\frac{1}{n_2})}}

Substitute the values  

test statistic :\frac{0.138-0.217}{\sqrt{0.1829(1-0.1829)(\frac{1}{180}+\frac{1}{230})}}

test statistic :  −2.053

Refer the z table for p value

p value = 0.0202

α= 0.05

Since p value < α

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So, Claim is true.

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4 years ago
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