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patriot [66]
4 years ago
9

A line passes through the origin and has a slope of 4. What is the equation of the line that is parallel to the first line and p

asses through the point (1, –2)?

Mathematics
1 answer:
N76 [4]4 years ago
4 0
Your answer will be y = 4x - 6

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Which statements verify that the solution set to lx + 31 < 5 is -8
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Given:

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(-1,4) and (3,16) in point slope form
Klio2033 [76]

Answer:

The equation of the line is y - 16 = 3(x - 3)

Step-by-step explanation:

To find the equation of this line, we first need to find the slope. To do that, we use the slope equation.

m(slope) = (y2 - y1)/(x2 - x1)

m = (16 - 4)/(3 - -1)

m = (16 - 4)/(3 + 1)

m = 12/4

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Now that we have the slope, we can use it and either point in point-slope form.

y - y1 = m(x - x1)

y - 16 = 3(x - 3)


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