All categories

3 years ago

What is the volume of the figure? Enter the answer in the box.

Mathematics

2 answers:

Annette [7]3 years ago

8 0

Answer:

Add all the numbers together in each box the take those two numbers and multply them.

Step-by-step explanation:

10+9+9= 28

18+4+10= 32

32x28= 896

I hope that helps.

insens350 [35]3 years ago

7 0

Answer:

896

Step-by-step explanation:

You might be interested in

Students on the CARE Team are selling puppies, yes, puppies! They earn $0.40 on each puppy they sell. Their goal is to earn more

cricket20 [7]

0.4 x >= 327 Divide by 0.4
x >= 327/0.4 which is not going to be an even number.
x >= 817. 5 puppies. So they need to sell 0.5 more puppies. Better round this quickly before someone decides to do something stupid to get the extra 1/2 puppy. For us it's simple. Just add a 1/2 puppy more.

x >= 818 puppies <<<<==== answer.

3 0

2 years ago

Jada Elena and Lin walked a total of 37 miles last week. jada walked 4 more miles that elena, and Lin walked 2 more miles than j

MA_775_DIABLO [31]

Answer:

Jada walked $13\ miles$

Elena walked $9\ miles$

Lin walked $15\ miles$

Step-by-step explanation:

Let

x----> total miles walked by Jada

y----> total miles walked by Elena

z----> total miles walked by Lin

we know that

$x+y+z=37$ -----> equation A

$x=y+4$ -----> $y=x-4$ ------> equation B

$z=x+2$ ------> equation C

Substitute equation C and equation B in equation A and solve for x

$x+(x-4)+(x+2)=37$

$3x=37+2$

$3x=39$

$x=13\ mi$

Find the value of y

$y=13-4=9\ mi$

Find the value of z

$z=13+2=15\ mi$

therefore

Jada walked $13\ miles$

Elena walked $9\ miles$

Lin walked $15\ miles$

3 0

2 years ago

54 ft = ____ yd 9. 11 L ≈ ____ qt 10. 80 g = ____ kg i need help with this

Alexxandr [17]

Answer:

54 ft = 18 yd 9. 11 L ≈ 11.6236 qt 10. 80 g = 0.08 kg

Step-by-step explanation:

3 0

2 years ago

Solve for x. a²x+(a-8)=(a+8)x

Sergio [31]

$a^2x+(a-8)=(a+8)x\\\\(a+8)x=a^2x+(a-8)\ \ \ \ |subtract\ a^2x\ from\ both\ sides\\\\(a+8)x-a^2x=a-8\\\\(a+8-a^2)x=a-8\ \ \ \ |divide\ both\ sides\ by\ (a+8-a^2)\\\\\huge\boxed{x=\frac{a-8}{a+8-a^2}}\to\huge\boxed{x=\frac{8-x}{a^2-a-8}}$