Answer:
1560
Step-by-step explanation:
1200*0.075 = 90
1200+90+90+90+90
Answer:
See explanation
Step-by-step explanation:
1. Given the expression
![\dfrac{\sqrt[7]{x^5} }{\sqrt[4]{x^2} }](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Csqrt%5B7%5D%7Bx%5E5%7D%20%7D%7B%5Csqrt%5B4%5D%7Bx%5E2%7D%20%7D)
Note that
![\sqrt[7]{x^5}=x^{\frac{5}{7}} \\ \\\sqrt[4]{x^2}=x^{\frac{2}{4}}=x^{\frac{1}{2}}](https://tex.z-dn.net/?f=%5Csqrt%5B7%5D%7Bx%5E5%7D%3Dx%5E%7B%5Cfrac%7B5%7D%7B7%7D%7D%20%5C%5C%20%5C%5C%5Csqrt%5B4%5D%7Bx%5E2%7D%3Dx%5E%7B%5Cfrac%7B2%7D%7B4%7D%7D%3Dx%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D)
When dividing
by
we have to subtract powers (we cannot subtract 4 from 7, because then we get another expression), so

and the result is ![x^{\frac{3}{14}}=\sqrt[14]{x^3}](https://tex.z-dn.net/?f=x%5E%7B%5Cfrac%7B3%7D%7B14%7D%7D%3D%5Csqrt%5B14%5D%7Bx%5E3%7D)
2. Given equation ![3\sqrt[4]{(x-2)^3} -4=20](https://tex.z-dn.net/?f=3%5Csqrt%5B4%5D%7B%28x-2%29%5E3%7D%20-4%3D20)
Add 4:
![3\sqrt[4]{(x-2)^3} -4+4=20+4\\ \\3\sqrt[4]{(x-2)^3}=24](https://tex.z-dn.net/?f=3%5Csqrt%5B4%5D%7B%28x-2%29%5E3%7D%20-4%2B4%3D20%2B4%5C%5C%20%5C%5C3%5Csqrt%5B4%5D%7B%28x-2%29%5E3%7D%3D24)
Divide by 3:
![\sqrt[4]{(x-2)^3} =8](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%28x-2%29%5E3%7D%20%3D8)
Rewrite the equation as:

Hence,

Answer:
Step-by-step explanation:
Basically, you want to know interest. I = prt is the formula. 'I' will be left blank b/c that's unknown. P is principal, 5000. R is rate, 4%, or 0.04 when turned into a decimal. T is time, 7 years. So now when using the formula, it will all become I = 5000(0.04)(7). What that means is you first multiply 5,000 by 0.04, getting 200. Then when you multiply 200 by 7, it's 1,400, which will leave you with I = 1,400. Interest is 1,400.
B=22.62
16/sin30=b/sin45
16sin45/sin30 =22.62
1. 5x+ 2(x+6)
= 5x+ 2x+ 2*6 (distributive property)
= 5x+ 2x+ 12
= (5x+ 2x)+ 12 (combine like terms)
= 7x+ 12
The correct answer is C. 7x+12~
2. <span> -3m + 3(m + 6)
= -3m+ 3m+ 3*6
= -3m+ 3m+ 18
= (-3m+ 3m)+ 18
= 18
The correct answer is D. 18~</span>