I need help for both of these !
1 answer:
4. 
<-8
First, you can multiply both sides of the inequality by 2 to cancel out the fraction to get:
w+3<-16
Then subtract 3 from both sides to get:
w<-19
Above is your answer
5. h≤
Like we did in the first one, multiply by 5 on both sides to get:
5h≤6h+3
Then subtract 6h from both sides to get
-1h≤3
Divide by -1 into both sides, and when you divide or multiply an inequality by a negative number, you flip the sign, so you would get
h≥-3
Above is your final answer
Hope this helped!
First, you can multiply both sides of the inequality by 2 to cancel out the fraction to get:
w+3<-16
Then subtract 3 from both sides to get:
w<-19
Above is your answer
5. h≤
Like we did in the first one, multiply by 5 on both sides to get:
5h≤6h+3
Then subtract 6h from both sides to get
-1h≤3
Divide by -1 into both sides, and when you divide or multiply an inequality by a negative number, you flip the sign, so you would get
h≥-3
Above is your final answer
Hope this helped!
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The diagram of the pentagon is missing, so i have attached it.
Answer:
|AE| = 130 m
|DE| = 150 m
Perimeter of pentagon = 720 m
Step-by-step explanation:
From the diagram, we can find AE from pythagoras theorem;
|AE| = √(|AA'|² + 50²)
Where AA' is the length from A to the perpendicular angle.
Now, AB = 150, and A'B is parallel to 30 m. Thus, A'B = 30
AA' = AB - A'B = 150 - 30
AA' = 120
Thus;
|AE| = √(120² + 50²)
|AE| = √(14400 + 2500)
|AE| = √16900
|AE| = 130
Similarly,
|DE| = √(|DD'|² + |ED'|²)
ED' = BC - 50
ED' = 140 - 50
ED' = 90
Also, DD' is parallel to AA' and is = 120
Thus;
|DE| = √(120² + 90²)
|DE| = √22500
|DE| = 150
Perimeter of pentagon = 150 + 130 + 150 + 150 + 140 = 720
