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olga55 [171]
3 years ago
6

I need help for both of these !

Mathematics
1 answer:
VLD [36.1K]3 years ago
6 0
4. \frac{w+3}{2}<-8
First, you can multiply both sides of the inequality by 2 to cancel out the fraction to get:
w+3<-16
Then subtract 3 from both sides to get:
w<-19 
Above is your answer

5. h≤\frac{6h+3}{5} 
Like we did in the first one, multiply by 5 on both sides to get: 
5h≤6h+3
Then subtract 6h from both sides to get
-1h≤3
Divide by -1 into both sides, and when you divide or multiply an inequality by a negative number, you flip the sign, so you would get
h≥-3
Above is your final answer

Hope this helped!
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<img src="https://tex.z-dn.net/?f=%20%7Bx%7D%5E%7B2%7D%20-%2022x%20%20%2B%20121" id="TexFormula1" title=" {x}^{2} - 22x + 121"
eduard

Let's factor x^2−22x+121

The middle number is -22 and the last number is 121. Factoring means we want something like

(x+_)(x+_)

Which numbers go in the blanks? We need two numbers that...

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Can you think of the two numbers?

Try -11 and -11:

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(x-11)(x-11)


Answer: (x-11)(x-11)


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